P (momentum) = mass x velocity
p = .5 x 20
p = 10
Answer:
south of east
Explanation:
= 3 m/s
= 
north of east
= 6 m/s
= 
south of east = 
north of east
x and y component of
x and y component of
Magnitude
Direction
The magnitude of the change in velocity vector is and the direction is south of east.
In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely due to the detection of A) methyl radical cation that has been lost from the spectrum.
<h3>Mass Spectrum</h3>
The m/z ratios of any ions contained in a sample displayed against their intensities that forms a mass spectrum.
The height of the peaks in any kind of mass spectrum denotes the relative abundance of the various components in the sample, and each peak in a mass spectrum displays a component that a distinct m/z is in the sample.
<h3>How do mass spectra function?</h3>
Only when a molecule has been transformed into a gas-phase ion can a mass spectrometer calculate the mass of the molecule.
In order to do this, it gives molecules an electrical charge and transforms the flow of electrically charged ions that results into a proportional electrical current that a data system can subsequently read.
<h3>Give an example of the mass spectral range.</h3>
Whenever any molecules are ionized in an ionization box, many different kinds of ions have been created.
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Complete Question
In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely to the detection of: _________-
A) Methyl Radical
B) Ethyl Radical
C) Propyl Radical
D) Butyl Radical
Answer:
V = 5.96 m/s
Explanation:
First we find the force required to move the car up the inclined plane. This force shall be equal to the component of the weight of the car that is parallel to the inclined plane. Hence,
F = W Sin θ
F = mg Sin θ
where,
F = Force = ?
m = mass of car = 1600 kg
g = 9.8 m/s²
θ = Inclination Angle = 20°
Therefore,
F = (1600 kg)(9.8 m/s²) Sin 20°
F = 5362.87 N
Now, we use power formula:
P = FV
V = P/F
where,
P = Engine Power = 32000 W
V = Maximum Velocity of Car = ?
Therefore,
V = 32000 W/5362.87 N
<u>V = 5.96 m/s</u>
1) 
We can solve this part by using Newton's second law:
(1)
where
F is the net force
m is the mass
a is the acceleration
There are two forces acting on the boat:
forward
backward
So the net force is
We know that the mass of the boat is
m = 1177.5 kg
So we can now use eq.(1) to find the acceleration:
2) 161.0 m
We can solve this part by using the following suvat equation:
where
s is the distance travelled
u is the initial velocity
t is the time
a is the acceleration
Here we have
u = 0 (the boat starts from rest)
Substituting t = 17.7 s, we find the distance covered:
3) 18.2 m/s
The speed of the boat can be found with the following suvat equation
where
v is the final velocity
u is the initial velocity
t is the time
a is the acceleration
In this case we have
u = 0 (the boat starts from rest)
And substituting t = 17.7 s, we find the final velocity:
And the speed is just the magnitude of the velocity, so 18.2 m/s.
