You have not mention here about those elements but the general concept for this is the:
uneven distribution ------> polar
even distribution -------> non-polar
Depending on the strictness of your teacher you can name it as either of the following:
2-methyl-propane or iso-propane
Answer:
The value of the
of the nitric acid is 1.2.
Explanation:
The initial concentration of nitric acid = c = 7.50 M

The dissociation constant of nitric acid = 
Degree of dissociation of nitric acid = 

initially
c 0 0
At equilibrium
(c-cα) cα cα
The expression of dissociation constant :
![K_a=\frac{[NO_3^{-}][H^+]}{[HNO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BNO_3%5E%7B-%7D%5D%5BH%5E%2B%5D%7D%7B%5BHNO_3%5D%7D)



The value of the
of the nitric acid is 1.2.
<span>The quadratic equation for the given solution would be
(x−√3+2i√5)(x−√3−2i√5)
if you will expand it further you will get
</span><span>x^2+x+5
and that will lead to the solution.
</span>