Answer:
The ball impact velocity i.e(velocity right before landing) is 6.359 m/s
Explanation:
This problem is related to parabolic motion and can be solved by the following equations:
----------------------(1)
---------(2)
----------------------- (3)
Where:
x = m is the horizontal distance travelled by the golf ball
is the golf ball's initial velocity
is the angle (it was a horizontal shot)
t is the time
y is the final height of the ball
is the initial height of the ball
g is the acceleration due gravity
V is the final velocity of the ball
Step 1: finding t
Let use the equation(2)
s
Substituting (6) in (1):
-------------------(4)
Step 2: Finding :
From equation(4)
m/s (8)
Substituting in (3):
v =42 .01 - 15.3566
V=26.359 m/s
Answer:
0.0239364 N
0.0057879 N
Explanation:
= Density of the gas
g = Acceleration due to gravity = 9.81 m/s²
V = Volume
Mass of rubber = 1.5 g
Buoyant force is given by
The buoyant force is 0.0239364 N
Net vertical force is given by
The net vertical force is 0.0057879 N
Answer:
The net torque is zero
Explanation:
Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.
