NO.OF.MOLES= MASS/ATOMIC MASS
THE ATOMICITY OF SULPHUR IS 8 AND ITS MASS NUMBER IS 32.
SO, THE ATOMIC MASS IS 256
NO.OF.MOLES= 53.7/256
= 537/2560
= 0.2097
Answer: the product is ketone or aldehyde
Explanation:
The first step is the conversion of acetal to hemiacetal in the presence of H3O+/ ROH, and then the final conversion of hemiacetal to ketone/aldehyde using
H3O+/ ROH...
Attached is the structural conversion
H2SO4 is referred to as a strong acid and is denoted as option A.
<h3>What is an Acid?</h3>
This refers to any substance which tastes sour when in water and changes the color of blue litmus paper to red. It is usually very corrosive and are used in industries for different functions.
H2SO4 is referred to as a strong acid because it dissociates completely in its aqueous solution or water.
Read more about Acid here brainly.com/question/25148363
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Answer : The mole fraction and partial pressure of
and
gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.
Explanation : Given,
Moles of
= 1.79 mole
Moles of
= 1.20 mole
Moles of
= 3.71 mole
Now we have to calculate the mole fraction of
and
gases.


and,


and,


Thus, the mole fraction of
and
gases are, 0.267, 0.179 and 0.554 respectively.
Now we have to calculate the partial pressure of
and
gases.
According to the Raoult's law,

where,
= partial pressure of gas
= total pressure of gas = 5.78 atm
= mole fraction of gas


and,


and,


Thus, the partial pressure of
and
gases are, 1.54, 1.03 and 3.20 atm respectively.