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marysya [2.9K]
3 years ago
10

Describe the historical development of building material being used in the construction indsury

Engineering
1 answer:
scZoUnD [109]3 years ago
4 0

Answer:

Construction, the techniques and industry involved in the assembly and ... Early building materials were perishable, such as leaves, branches, and animal hides. ... The well-developed masonry technology of Mesopotamia was used to build large ... although its precise description is unknown; the concealed faces of stones

Explanation:

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An architect position requires an internship or residency true or false
Helga [31]

False

Explanation:

Residency is a term in medicine that means a three plus training program in medical specialty. An architect is a program in the engineering field that requires an internship after graduation to equip a graduate architect with field experience that involve working close with experienced professionals in the same field. During this 12 month internship period, a graduate is trained on how to perform the real job through exposure to projects in that field.

Learn More

Residency in medicine :brainly.com/question/13357986

Keywords : architect, internship, residency

#LearnwithBrainly

4 0
3 years ago
If the power factor is corrected to 0.95 lagging, keeping the receiving end MVA constant, what will be the new voltage regulatio
k0ka [10]

Answer:

Due to power factor correction; voltage regulation is improved and efficiency is increased.

Explanation:

Power Factor Vs Voltage Regulation:

When the power factor is improved, the current in the system decreases as power factor and current have inverse relation.

When current decreases, the corresponding voltage drops in the system decreases as the voltage and current are directly proportional.

Since the voltage drop decreases, the voltage regulation improves since the voltage regulation is given by

Voltage regulation = (Vin - Vout)/Vout x 100%

Vout will be greater due to less voltage drop.

Power Factor Vs Efficiency:

Efficiency is given by

η = Pout/Pin

but Pin = Pout + Plosses

η = Pout/Pout + Plosses

When power factor is improved, the current decreases, the decrease in current reduces the power losses since the losses are directly proportional to the square of current (I²R) therefore, decrease in Plosses results in the increased efficiency of the system.

5 0
4 years ago
1. What are hand tools ? *
Mamont248 [21]

Answer:

Microsoft Word - Hand tools SON

8 0
3 years ago
3.24 Program: Drawing a half arrow (Java) This program outputs a downwards facing arrow composed of a rectangle and a right tria
Lostsunrise [7]

Answer:

Here is the JAVA program:

import java.util.Scanner; // to get input from user

public class DrawHalfArrow{ // start of the class half arrow

public static void main(String[] args) { // starts of main() function body

    Scanner scnr = new Scanner(System.in); //reads input

int arrowBaseHeight = 0; // stores the height of arrow base

int arrowBaseWidth  = 0; // holds width of arrow base

int arrowHeadWidth = 0; // contains the width of arrow head

// prompts the user to enter arrow base height, width and arrow head width

System.out.println("Enter arrow base height: ");

arrowBaseHeight = scnr.nextInt(); // scans and reads the input as int

System.out.println("Enter arrow base width: ");

arrowBaseWidth = scnr.nextInt();

/* while loop to continue asking user for an arrow head width until the value entered is greater than the value of arrow base width */

while (arrowHeadWidth <= arrowBaseWidth) {

    System.out.println("Enter arrow head width: ");

    arrowHeadWidth = scnr.nextInt(); }

//start of the nested loop

//outer loop iterates a number of times equal to the height of the arrow base

 for (int i = 0; i < arrowBaseHeight; i++) {

//inner loop prints the stars asterisks

      for (int j = 0; j <arrowBaseWidth; j++) {

          System.out.print("*");        } //displays stars

          System.out.println();          }

//temporary variable to hold arrowhead width value

int k = arrowHeadWidth;

//outer loop to iterate no of times equal to the height of the arrow head

for (int i = 1; i <= arrowHeadWidth; i++)

{     for(int j = k; j > 0; j--)     {//inner loop to print stars

       System.out.print("*");    } //displays stars

   k = k - 1;

   System.out.println(); } } } // continues to add more asterisks for new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.

The loop is used to output an arrow base of height arrowBaseHeight. So point (1) is satisfied.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow. So (2) is satisfied.

A temporary variable k is used to hold the original value of arrowHeadWidth so that it keeps safe when modification is done.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head. So (3) is satisfied.

The value of temporary variable k is decreased by 1 so the next time it enters  the nested for loop it will be one asterisk lesser.

The screenshot of output is attached.

8 0
4 years ago
3. What is the mechanical advantage of the pulley system shown below? HII TAI 190 O A1 O E.2 OC.3 OD 4​
Contact [7]

Answer:

I don't know ☺️☺️☺️❌‼️

Explanation:

I don't understand this question

7 0
3 years ago
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