1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kumpel [21]
2 years ago
12

Cierto laboratorio está probando una nueva vacuna contra el SARS coV 2 y la 1ra fase incluyesolo 8 voluntarios de tal forma que

se pueda evaluar la seguridad del fármaco y detener eltratamiento si se detectan efectos dañinos. ¿Cuántas secuencias de pacientes se pueden formar sise dispone de 10 voluntarios?
Engineering
1 answer:
madreJ [45]2 years ago
8 0

Answer:

puede que la vacuna no sea segura y se contagien y surga una nueva enfermedad y es lo único que se me ocurre

You might be interested in
2. Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a system optimizes its performan
oee [108]

The python program is an implementation of the Ackermann function that a system optimizes its performance of recursion.

As per the question,

Here is an implementation of the Ackermann function in Python:

<em />

<em>def ackermann(m, n):</em>

<em>    if m == 0:</em>

<em>        return n + 1</em>

<em>    elif n == 0:</em>

<em>        return ackermann(m - 1, 1)</em>

<em>    else:</em>

<em>        return ackermann(m - 1, ackermann(m, n - 1))</em>

<em />

<em># get input values for m and n from the user</em>

<em>m = int(input("Enter an integer value for m: "))</em>

<em>n = int(input("Enter an integer value for n: "))</em>

<em />

<em># calculate and print the result of the Ackermann function</em>

<em>result = ackermann(m, n)</em>

<em>print("Ackermann ({},{}) = {}".format(m, n, result))</em>

This implementation follows the logic described in the prompt, using a recursive function to calculate the result of the Ackermann function for the given values of m and n.

To learn more about the Python Program click here:

brainly.com/question/15061326

#SPJ1

<em />

5 0
1 year ago
Part A Engineering stress and strain are calculated using the actual cross-sectional area and length of the specimen. True or fa
Galina-37 [17]

Answer: True

Explanation:

Engineering stress is the applied load divided by the original cross-sectional area of a material. It is also known as nominal stress. It can also be defined as the force per unit area of a material. Engineering Stress is usually in large numbers.

While Engineering strain is the amount that a material deforms per unit length in a tensile test.  It can also be defined as extension per unit length. It has no unit as it is a ratio of lengths. Engineering Strain is in small numbers.

5 0
3 years ago
Read 2 more answers
A master precision square is used to validate the
kumpel [21]

Answer:

me you same I didn't understand good luck

4 0
2 years ago
Velocity boundary layer thickness over a intermal fixed horizontal flat plate is the________ distance required for the fluid vel
antoniya [11.8K]

Answer:

Velocity boundary layer thickness over an internal or internal fixed flat plate is  normal to surface distance  required for the fluid velocity to attain the 99% of the free stream velocity value.

Explanation:

The affirmation is the current definition of velocity boundary layer thickness.

4 0
3 years ago
A rigid tank with a total volume of 0.05 m3 initially contains a two-phase liquid-vapor mixture of water at a pressure of 15 bar
Westkost [7]

Answer:

a) m_{2} = 0.753\,kg, b) Q_{in} = 2122.963\,kJ

Explanation:

A rigid tank means a storage whose volume is constant. Process is entirely isobaric. Initial and final properties of water are included below:

State 1 - Gas-Vapor Mixture

P = 1500\,kPa

T = 198.29^{\textdegree}C

\nu = 0.02726\,\frac{m^{3}}{kg}

u = 1192.94\,\frac{kJ}{kg}

h_{g} = 2791.0\,\frac{kJ}{kg}

x = 0.2

State 2 - Gas-Vapor Mixture

P = 1500\,kPa

T = 198.29^{\textdegree}C

\nu = 0.06643\,\frac{m^{3}}{kg}

u = 1718.12\,\frac{kJ}{kg}

h_{g} = 2791.0\,\frac{kJ}{kg}

x = 0.5

The model for the rigid tank is created by using the First Law of Thermodynamics:

Q_{in} - (m_{1}-m_{2})\cdot h_{g} = m_{2}\cdot u_{2}-m_{1}\cdot u_{1}

Initial and final masses are:

m_{1} = \frac{V_{1}}{\nu_{1}}

m_{1} = \frac{0.05\,m^{3}}{0.02726\,\frac{m^{3}}{kg} }

m_{1} = 1.834\,kg

m_{2} = \frac{V_{2}}{\nu_{2}}

m_{2} = \frac{0.05\,m^{3}}{0.06643\,\frac{m^{3}}{kg} }

m_{2} = 0.753\,kg

a) The final mass within the tank is:

m_{2} = 0.753\,kg

b) The total amount of heat transfer is:

Q_{in} = m_{2}\cdot u_{2}-m_{1}\cdot u_{1}+ (m_{1}-m_{2})\cdot h_{g}

Q_{in} = (0.753\,kg)\cdot (1718.12\,\frac{kJ}{kg} )- (1.834\,kg)\cdot (1192.94\,\frac{kJ}{kg} ) + (1.081\,kg)\cdot (2791.0\,\frac{kJ}{kg} )

Q_{in} = 2122.963\,kJ

5 0
3 years ago
Other questions:
  • Define a public static method named s2f that takes two String arguments, the name of a file and some text. The method creates th
    5·1 answer
  • Main technologies used in atms vending machines game consoles and microwave ovens
    6·1 answer
  • During the collision, is the magnitude of the force of asteroid A on asteroid B greater than, less than, or equal to the magnitu
    11·2 answers
  • Air enters the compressor of an ideal Brayton refrigeration cycle at 100 kPa, 270 K. The compressor pressure ratio is 3, and the
    13·1 answer
  • What i s the value of a capacitor with 250 V applied and has 500 pC of charge? (a) 200 uF (b) 0.5 pF (c) 500 uF (d) 2 pF
    15·1 answer
  • Ball joints on a vehicle equipped with MacPherson struts are being inspected for wear. Which of the following would be the corre
    11·1 answer
  • A local surf report provides the height of the wave from the trough to the crest of the wave. How does this relate to the wave’s
    11·1 answer
  • What are the main causes of injuries when using forklifts?
    5·1 answer
  • Proper handling of blueprints includes which of the following
    5·1 answer
  • Select the correct answer.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!