Answer:
Required charge 
.
Explanation:
Given:
Diameter of the isolated plastic sphere = 25.0 cm
Magnitude of the Electric field = 1500 N/C
now
Electric field (E) is given as:
where,
k = coulomb's constant = 9 × 10⁹ N
q = required charge
r = distance of the point from the charge where electric field is being measured
The value of r at the just outside of the sphere = 
thus, according to the given data
or
or
Required charge .
Now,
the number of electrons (n) required will be
or
or
(4) Elevations:
Point A: 900 ft
Point B: 900 ft
Point C: 1500 ft
Point D: 1000 ft
(5) Contour interval: 100 ft
(6) Plot #1 best fits the profile seen in the contour map.
Since V is 5 times larger than C
A) 0V = 25C
25C to 0C = -25
-25 / 5 = -5
so 0C = -5 V
B)
20V x 5 = 100 C
Answer:
The objects must be different temperatures.
Explanation:The objects must be different temperatures. eat will flow from Object 1 to Object 2 in examples 1, 2, and 4, and heat will flow from Object 2 to Object 1 in Example 3. Which factors affect heat transfer between a warm and a cool substance?
Answer: 17.5 kN
Explanation:
force downward on student:
mg+142-mv^2/r=0
mg=mv^2/r-142
mv^2/r=mg+142
at bottom, apparent weight
weight=mg+mv^2/r=mg+mg+142
apparent weight= 89(2g)+142
for force at bottom, reverse v^2/r
force=m(g+v^2/r) = 89 ( 9.8 + v^2 / 19 )
F = mg + mv^2 / r
F = mg + mg + 142 = 2mg + 142 = 2 x 89 x 9.8 + 142 = 17.5 kN
