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laiz [17]
3 years ago
14

Please help !

Physics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

2179412787.20000

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A push on a textbook with 10 N moves it to a distance of 2 cm. How much force is need to move it to 4 cm?
uysha [10]

Answer:

20N

Explanation:

Ratio of N to cm-

10:2

so to make 2=4 times 2 so The ratio is now-

20:4

so to move 4 cm you need to push 20N.

8 0
3 years ago
A man claims that he can hold onto a 16.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man
Anna007 [38]

Answer:

F = -8440.12 N

the magnitude of the average force needed to hold onto the child is 8440.12 N

Explanation:

Given;

Mass of child m = 16 kg

Speed of each car v = 59.0 mi/h = 26.37536 m/s

Time t = 0.05s

Applying the impulse momentum equation;

Impulse = change in momentum

Ft = ∆(mv)

F = ∆(mv)/t

F = m(∆v)/t

Where;

F = force

t = time

m = mass

v = velocity

Since the final speed of the car is zero(at rest) then;

∆v = 0 - v = -26.37536 m/s

Substituting the given values;

F = 16×-26.37536/0.05

F = -8440.1152 N

F = -8440.12 N

the magnitude of the average force needed to hold onto the child is 8440.12 N

5 0
3 years ago
Newton’s law of universal gravitation stars that every object in the universe attracts every other object
LenaWriter [7]

Yes it does !  Uh huh. Right you are. Truer words are seldom written.

You have quoted the law quite accurately but also incompletely.  

Do you have a question to ask ?

4 0
3 years ago
An airplane moves through the air at a constant speed. The engines’ thrust applies a force in the direction of motion, and this
lord [1]

Explanation:

This is because the drag force suffered by the aircraft is proportional to the speed at which it travels. The thrust of the engines prints a speed to the plane and this speed prints a drag force, always reaching an equilibrium point of these two forces where the speed of the plane is constant and the acceleration is equal to zero.

Therefore, by reducing the thrust, the drag force is greater and the plane begins to decrease its speed, until it reaches the point where the new drag force is matched with the new thrust force, giving it a new final speed , without acceleration.

8 0
3 years ago
A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta
My name is Ann [436]

Answer:

a).K=528.92 \frac{N}{m}

b).m=4.84kg

Explanation:

a).

The work of the spring is find by the formula:

w_s =\frac{1}{2}*k*x^2

So knowing the work can find the constant K'

3.2J =\frac{1}{2}*k*(0.11m)^2

Solve for K'

K=\frac{2*W_s}{x^2}=\frac{2*3.2J}{0.11m^2}

K=528.92 \frac{N}{m}

b).

The force of the spring realice a motion so using the force and knowing the accelerations can find the mass

F=m*a

m=\frac{F}{a}=\frac{K*x}{a}

m=\frac{528.9*0.11m}{12m/s^2}

m=4.84kg

8 0
3 years ago
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