All categories

3 years ago

How do atoms form double or triple covalent bonds?

Chemistry

1 answer:

Alex17521 [72]3 years ago

7 0

Answer:

Covalent bonding occurs when electrons are shared between atoms. Double and triple covalent bonds occur when four or six electrons are shared between two atoms, and they are indicated in Lewis structures by drawing two or three lines connecting one atom to another.

Explanation:

You might be interested in

Tried solving this multiple ways, but keep getting the wrong answer. So, I would appreciate the help. Thank you.

Aliun [14]

Answer:

I can give you the definition ... That might help cause I honestly don't kno the answer either ;-;

Explanation:

When used as a diacritic mark, the term dot is usually reserved for the interpunct, or to the glyphs 'combining dot above' and 'combining dot below' which may be combined with some letters of the extended Latin alphabets in use in Central European languages and Vietnamese.

Here is an example:

The dot product between a unit vector and itself is also simple to compute. In this case, the angle is zero and cosθ=1. Given that the vectors are all of length one, the dot products are i⋅i=j⋅j=k⋅k=1.

5 0

3 years ago

Calculate the change in energy when 75.0 grams of water drops from 31.0C to 21.6.

zysi [14]

Answer: Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

5 0

4 years ago

Read 2 more answers

Calculate the molarity of each of the following

Alenkasestr [34]

Answer:

a. 1.21M

b. 0.119M

c. 0.00496M

Explanation:

Molarity, M, is an unit of concentration defined as the ratio between moles of solute and liters of solution:

a. 4.35 mol LiCl / 3.60L = 1.21M

b. 29.43gC6H12O6 * (1mol / 180.16g) = 0.1634moles / 1.37L = 0.119M

Molar mass C6H12O6: 180.16g/mol

c. 34.5mg NaCl = 0.0345g * (1mol / 58.44g) = 5.9x10⁻⁴moles / 0.1191L = 0.00496M

8 0

3 years ago

Compounds A, B, and C react according to the following equation. 3A(g) + 2B(g) 2C(g) At 100°C a mixture of these gases at equili

Vedmedyk [2.9K]

Answer:

The value of Kc for the reaction is 3.24

Explanation:

A reversible chemical reaction, indicated by a double arrow, occurs in both directions: reagents transforming into products ( direct reaction) and products transforming back into reagents (inverse reaction)

Chemical Equilibrium is the state in which direct and indirect reactions have the same reaction rate. Then taking into account the rate constant of a direct reaction and its inverse the chemical constant Kc is defined.

Being:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients, the equilibrium constant with the following equation:

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also raised to their stoichiometric coefficients.

Then, in the reaction 3A(g) + 2B(g) ⇔ 2C(g), the constant Kc is:

$Kc=\frac{[C]^{2} }{[A]^{3} *[B]^{2} }$

where:

[A]= 0.855 M
[B]= 1.23 M
[C]= 1.75 M

Replacing:

$Kc=\frac{1.75^{2} }{0.855^{3}*1.23^{2} }$

Solving you get:

Kc=3.24

The value of Kc for the reaction is 3.24

8 0

3 years ago

5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats

ahrayia [7]

Given :

If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs.

To Find :

The new volume of the gas.

Solution :

Since, their is no information about pressure, so we will assume that pressure is constant.

We know, relation between temperature and volume in constant pressure is :

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Putting all given values in above equation, we get :

$V_2 = \dfrac{V_1\times T_2}{T_1}\\\\V_2 = \dfrac{2.2\times (180+273)}{(380+273)}\\\\V_2 = 1.53 \ liters$

Hence, this is the required solution.

8 0

3 years ago