(a) The coil's self-inductance is 7.26 mH.
(b) The self-induced emf in the coil is 7.26 V
(c) The direction of the induced emf is from b to a.
<h3>Coil's self-inductance</h3>
L = N²μA/I
L = (600² x 4π x 10⁻⁷ x 6.9 x 10⁻⁴)/(0.043)
L = 7.26 x 10⁻³ H
L = 7.26 mH
<h3>Self-induced emf in the coil</h3>
emf = N(ΔBA)/t
where;
- B is magnetic field
- A is area
- N is number of turns
- t is time
B = μNI/L
B1 = (4π x 10⁻⁷ x 600 x 5)/0.043
B1 = 0.0876 T
B2 = (4π x 10⁻⁷ x 600 x 2)/0.043
B2 = 0.035 T
emf = NΔBA/t
emf = (600)(0.0876 - 0.035)(6.9 x 10⁻⁴) / (3 x 10⁻³)
emf = 7.26 V
The direction of the induced emf is always opposite to the direction of the applied current.
Thus, the direction of the induced emf is from b to a.
Learn more about induced emf here: brainly.com/question/13744192
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Answer:
0.83 J of work
Explanation:
2 J of work is required to stretch a spring from 34cm to 46cm
So that is 12cm stretched with 2 J of work
We can make that 6cm for 1 J of work
So, we need the find the work for stretching 36cm to 41cm
Which is 5cm
So, What is the work required to stretch 5cm?
1 J of work for 6cm
x work for 5cm
So, by proportion method
1 : 6 :: x : 5
6 * x = 1 * 5
6x = 5
x = 5/6
= 0.83
So to stretch 36cm to 41cm we need 0.83 J of work
Electromagnetic is the relationship exists between wavelength and frequency.
Answer:
-4.72005 m/s
0 m/s
Explanation:
Displacement = 5220 km
Time = 12.8 days
The average velocity is given by
The average for the return flight is -4.72005 m/s
When the total displacement is divided by the total time of a journey then we get the average velocity.
Displacement is the minimum distance between the initial and final points of the journey.
Here, the displacement of the whole episode is 0 as the initial and final point is zero.
Hence, the average velocity for the whole episode is 0 m/s
-Geographic north and south poles are determined by the earth's spin.
-Magnetic north and south is determined by the direction a compass points.
Hope this helps,
kwrob
