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romanna [79]
3 years ago
11

12. Which gas has the greatest kinetic energy at STP?

Chemistry
1 answer:
balandron [24]3 years ago
4 0

Answer:

d. none of the above (all have the same kinetic energy)

Explanation:

The kinetic theory of gases states that the molecules of an ideal gas experience a constant random motion.

At standard temperature and pressure (STP), the kinetic energy of an ideal gas such as hydrogen, argon, neon, sodium, oxygen, helium, magnesium, beryllium, nitrogen, carbon, fluorine, chlorine etc are all the same.

The standard temperature and pressure (STP) of an ideal gas is 273K and 100 kPa.

Hence, all of the gases have the same kinetic energy at standard temperature and pressure (STP).

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

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Indicate which solution in each pair has the lower pH. Your response should be a four letter "word". The first letter should be
JulijaS [17]

Answer:

bcfh

Explanation:

HClO₄ reacts with water thus:

HClO₄ + H₂O → H₃O⁺ + ClO₄⁻

That means HClO₄ produce H₃O⁺ that decreases pH. That means the higher concentration of HClO₄ decreases pH. Thus, lower pH will be:

b) 0.2 M HClO4

The reaction of NaClO₄ is:

NaClO₄ + H₂O → OH⁻ + HClO₄ + Na⁺

The higher concentration of NaClO₄ the higher production of OH⁻ that increase pH, that means the lower concentration of NaClO₄ the lower pH, thus, the answer is:

<em>c) 0.1 M NaClO or</em>

HF reacts with water thus;

HF ⇄ H⁺ + F⁻

The equilibrium constant is:

k = [H⁺] [F⁻] / [HF] = 3,5x10⁻⁴

For HNO₂ equilibrium is:

HNO₂ ⇄ H⁺ + NO₂⁻

k = [H⁺] [NO₂⁻] / [HNO₂] = 4,5x10⁻⁴

As k value is higher for HNO₂, the concentration of H⁺ will be higher in this system doing the HNO₂ with the lower pH.

f) 0.1 M HNO2

NaOH is a strong base that produce OH⁻ that increase pH, pure water is neutral, thus, the lowe pH is:

h) pure water

I hope it helps!

7 0
4 years ago
A bolt of lightning is an example of static discharge.<br> TRUE<br> FALSE
Maslowich

Answer:

True

Explanation:

6 0
3 years ago
. Which of the following is NOT a common state of matter under room temperature conditions?
storchak [24]

Answer: plasma

Explanation:

4 0
3 years ago
Read 2 more answers
What masses of sodium chloride, magnesium chloride, sodium sulfate, calcium chloride, potassium chloride, and sodium bicarbonate
andreyandreev [35.5K]

Answer:

NaCl: 184g

MgCl₂: 6.60g

Na₂SO₄: 9.26g

CaCl₂: 1.28g

KCl: 0.70g

NaHCO₃: 0.13g

Explanation:

To convert these concentrations to masses we need to convert molarity to moles and moles to grams using molar mass of each salt:

[CaCl₂] = [Ca²⁺] = 0.0115M

[HCO₃⁻] = [NaHCO₃] = 0.0015M

[SO₄²⁻] = [Na₂SO₄] = 0.0652M

[Mg²⁺] = [MgCl₂] = 0.0693M

[K⁺] = [KCl] = 0.0094M

And using the concentration of Cl⁻:

[Cl⁻] = [NaCl] + 2[MgCl₂] + 2[CaCl₂] + [KCl]

[3.32] = [NaCl] + 2[0.0693] + 2[0.0115] + [0.0094]

[NaCl] = 3.149M

The masses you need are:

<em>NaCl (Molar mass: 58.44g/mol):</em>

3.149mol/L * 1L *  (58.44g/mol) =

<h3>184g NaCl</h3><h3 />

<em>MgCl₂ (Molar mass: 95.211g/mol):</em>

0.0693mol/L * 1L *  (95.211g/mol) =

<h3>6.60g MgCl₂</h3><h3 />

Na₂SO₄<em> (Molar mass: 142.04g/mol):</em>

0.0652mol/L * 1L *  (142.04g/mol) =

<h3>9.26g Na₂SO₄</h3>

CaCl₂<em> (Molar mass: 110.98g/mol):</em>

0.0115mol/L * 1L *  (110.98g/mol) =

<h3>1.28g CaCl₂</h3>

KCl<em> (Molar mass: 74.55g/mol):</em>

0.0094mol/L * 1L *  (74.55g/mol) =

<h3>0.70g KCl</h3><h3 />

<em>NaHCO₃ (Molar mass: 84g/mol):</em>

0.0015mol/L * 1L *  (84g/mol) =

<h3>0.13g NaHCO₃</h3>

7 0
3 years ago
100 mL of a buffer that consists of 0.20 M NH3 and 0.20 M NH4Cl is titrated with 25 mL of 0.20 M HCl. Calculate the pH of the re
Marrrta [24]

Answer:

pH = 9.03

Explanation:

The equilibrium of the NH₄Cl / NH₃ buffer in water is:

NH₃ + H₂O ⇄ NH₄⁺ + OH⁻

Initial moles of both NH₃ and NH₄⁺ are:

0.100L ₓ (0.20 mol / L) = <em>0.0200 moles </em>

The NH₃ reacts with HCl producing NH₄⁺, thus:

NH₃ + HCl → NH₄⁺ + Cl⁻

<em>That means, moles of HCl added to the solution are the same moles are consumed of NH₃ and produced of NH₄⁺</em>

Moles added of HCl were:

0.025L ₓ (0.20mol / L) = 0.0050 moles of HCl. Thus, final moles of NH₃ and NH₄⁺ are:

NH₃: 0.0200 moles - 0.0050 moles = 0.0150 moles

NH₄⁺: 0.0200 moles + 0.0050 moles = 0.0250 moles.

Using H-H equation for bases:

pOH = pKb + log [NH₄⁺] / [NH₃]

<em>Where pKb is -log Kb =</em><em> 4.745</em><em>.</em>

Replacing:

pOH = 4.745 + log 0.0250mol / 0.0150mol

pOH = 4.967

As pH = 14- pOH

<em>pH = 9.03</em>

<em />

6 0
3 years ago
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