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3 years ago

PLEASE HELP ME WITH THIS ONE QUESTION

Physics

1 answer:

yaroslaw [1]3 years ago

5 0

Answer:

Energy = 1.5032*10^(-10) Joules

Explanation:

By Einstein's relativistic energy equation, we know that the energy of a given particle is given by:

Energy = rest energy + kinetic energy.

= m*c^2 + (γ - 1)*mc^2

Where γ depends on the velocity of the particle.

But if the proton is at rest, then the kinetic energy is zero, and γ = 1

Then the energy is just given by:

Energy = m*c^2

Where we know that:

mass of a proton = 1.67*10^(-27) kg

speed of light = c = 2.9979*10^(8) m/s

Replacing these in the energy equation, we get:

Energy = ( 1.6726*10^(-27) kg)*( 2.9979*10^(8) m/s)^2

Energy = 1.5032*10^(-10) kg*m^2/s^2

Energy = 1.5032*10^(-10) J

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A star is estimated to be 4.8 km away from the earth. When we see this star in the night sky how old is the image. Let the speed

andre [41]

Time = distance / speed

Time = (4,800 meters) / (3 x 10⁸ m/s)

Time = 0.000016 second

This number is not one of the choices on the list. My hunch is that you copied the distance wrong.

If the estimated distance to the star is actually 4.8 x 10¹⁵ km, instead of 4.8 km, then the answer would be close to 500 years (B).

There's no way a star can be "4.8 km away from the Earth". You can walk that far in about an hour, and passenger jet airplanes fly twice as far as that away from the Earth !

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5.00-kg particle starts from the origin at time zero. Its velocity as a function of time is given by v =6t^2 i + 2t j where v is

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The concept of derivatives and integrals allows to find the results for the questions are the motion of a particle where the speed depends on time are:

a)the position is: r = 2 t³ i + t² j

b) the position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

c) The acceleration is: a = 12 t i + 2 j

d) the force is: F = 60 t i + 10 j

e) the torque is: τ = 40 t³ k^

f) tha angular momentum is: L = 4t³ - 6 t² k^

g) The kinetic energy is: K = 2 m t² (9t² +1)

h) The power is: P = 2m (36 t³ + 2t)

Kinematics studies the movement of bodies, looking for relationships between position, speed and acceleration.

a) They indicate the function of speed.

v = 6 t² i + 2t j

Ask the function of the position. The velocity is defined by the variation of the position with respect to time

v = $\frac{dr}{dt}$

dr = v dt

we substitute and integrate.

∫ dr = ∫ (6 t² i + 2t j) dt

r - 0 = $6 \frac{t^3 }{3} \ \hat i + 2 \frac{t^2}{2 \ \hat j }$

r = 2 t³ i + t² j

b) The position of the body on the y axis is a parabola and on the x axis it is a cubic function.

c) Acceleration is defined as the change in velocity with time.

$a = \frac{dv}{dt}$

a = $\frac{d}{dt} \ (6t^2 i + 2t j)$

a = 12 t i + 2 j

d) Newton's second law states that force is proportional to mass times the body's acceleration.

F = ma

F = m (12 t i + 2 j)

F = 5 12 t i + 2 j

F = 60 t i + 10 j

e) Torque is the vector product of the force and the distance to the origin.

τ = F x r

The easiest way to write these expressions is to solve for the determinant.

$\tau = \left[\begin{array}{ccc}i&j&k\\F_x&F_y&F_z\\x&y&z\end{array}\right]$

$\tau = \left[\begin{array}{ccc}i&j&k\\60t &10&0\\2t^3 &t^2&0\end{array}\right]$

τ = (60t t² - 2t³ 10) k

τ = 40 t³ k ^

f) Angular momentum

L = r x p

L =rx (mv)

L = m (rxv)

The easiest way to write these expressions is to solve for the determinant.

$\left[\begin{array}{ccc}i&j&k\\2t^3 &t^2&0\\6t^2&2t&0\end{array}\right]$

L = (4t³ - 6 t²) k

g) The kinetic energy is

K = ½ m v²

K = ½ m (6 t² i + 2t j) ²

K = m 18 t⁴ + 2t²

K = 2 m t² (9t² +1)

h) Power is work per unit time

P = $\frac{dW}{dt}$ dW / dt

The relationship between work and kinetic energy

W = ΔK

P = $2m \ \frac{d}{dt} ( 9 t^4 + t^2)$

p = 2m (36 t³ + 2t)

In conclusion with the concept of derivatives and integrals we can find the results for the questions are the motion of a particle where the speed depends on time are:

a) The position is: r = 2 t³ i + t² j

b) The position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

c) The acceleration is: a = 12 t i + 2 j

d) The force is: F = 60 t i + 10 j

e) The torque is: τ = 40 t³ k^

f) The angular momentum is: L = 4t³ - 6 t² k^

g) The kinetic energy is: K = 2 m t² (9t² +1)

h) The power is: P = 2m (36 t³ + 2t)

Learn more here: brainly.com/question/11298125

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Answer:

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Explanation:

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$K_{c} = K_{b}$

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$\frac{v_{c}}{v_{b}}=\sqrt{\frac{m_{b}}{m_{c}} }$

The ratio is obtained by multiplying each side by $\frac{m_{c}}{m_{b}}$ :

$\frac{p_{c}}{p_{b}}=\frac{m_{c}}{m_{b}}\cdot \sqrt{\frac{m_{b}}{m_{c}} }$

$\frac{p_{c}}{p_{b}}= \sqrt{\frac{m_{c}}{m_{b}} }$

The value of this ratio is:

$\frac{p_{c}}{p_{b}}\approx 0.507$

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