Answer:
1 because I looked it up for sure
Answer:
2f
Explanation:
The formula for the object - image relationship of thin lens is given as;
1/s + 1/s' = 1/f
Where;
s is object distance from lens
s' is the image distance from the lens
f is the focal length of the lens
Total distance of the object and image from the lens is given as;
d = s + s'
We earlier said that; 1/s + 1/s' = 1/f
Making s' the subject, we have;
s' = sf/(s - f)
Since d = s + s'
Thus;
d = s + (sf/(s - f))
Expanding this, we have;
d = s²/(s - f)
The derivative of this with respect to d gives;
d(d(s))/ds = (2s/(s - f)) - s²/(s - f)²
Equating to zero, we have;
(2s/(s - f)) - s²/(s - f)² = 0
(2s/(s - f)) = s²/(s - f)²
Thus;
2s = s²/(s - f)
s² = 2s(s - f)
s² = 2s² - 2sf
2s² - s² = 2sf
s² = 2sf
s = 2f
Answer:
During an earthquake, seismic waves travels through the Earth's interior as body or p waves.
Explanation:
If neither of the bold words look familiar from your lesson feel free to ignore this answer
Let the Blaise runs for time "t" to complete the race
so the total distance he moved is given by
![d_1 = 1* t](https://tex.z-dn.net/?f=d_1%20%3D%201%2A%20t)
Now Issac runs for time t = "t - 2*60"
because it took rest for 2 minutes
![d_2 = 2*(t - 120)](https://tex.z-dn.net/?f=d_2%20%3D%202%2A%28t%20-%20120%29)
now it is given that Blaise wins by 10 m distance
![d_1 - d_2 = 10](https://tex.z-dn.net/?f=d_1%20-%20d_2%20%3D%2010)
![1* t - 2*(t - 120) = 10](https://tex.z-dn.net/?f=1%2A%20t%20-%202%2A%28t%20-%20120%29%20%3D%2010)
![t - 2t + 240 = 10](https://tex.z-dn.net/?f=t%20-%202t%20%2B%20240%20%3D%2010)
![t = 230 s](https://tex.z-dn.net/?f=t%20%3D%20230%20s)
now the distance moved by Blaise is given by
![d_1 = 1*230 = 230 m](https://tex.z-dn.net/?f=d_1%20%3D%201%2A230%20%3D%20230%20m)
Answer:
Neutrally charged!!!!!!!!!!!!!!!!!!!!!
Explanation: