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Elza [17]
3 years ago
10

When you cook a marshmallow on a metal poker tool over an open flame, energy is transferred. Identify the three different ways t

hermal energy is transferred in this situation. Be sure to name the specific places or phenomenon in this system where each of the types of thermal energy transfer is occurring and the direction the energy is being transferred (from what to what).

Physics
1 answer:
sergejj [24]3 years ago
4 0

Answer:

The three ways thermal energy is transferred are;

1) Conduction

2) Convection

3) Radiation

Explanation:

1) The conduction of the heat from the open flame to the marshmallow is through the direct contact of the flame with the marshmallow, such that the flame the region of the combustion reaction, that produces light and heat touches the marshmallow

2) The convection process is the transfer of heat from the rising heated combustion products, as well as the heated air that rises from the flame

3) The radiation heat transfer is the transfer of the heat from the fire to the marshmallows directly by the heat the moves in the form of electromagnetic waves at temperatures above 1000 K, without the need for a medium, such that the marshmallow can be heated by the heat coming from side of the flame.

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Answer:

B) waves speed up

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Explanation:

The index of refraction of a material is the ratio between the  speed of light in a vacuum and the speed of light in that medium:

n=\frac{c}{v}

where

c is the speed of light in a vacuum

v is the speed of light in the medium

We can re-arrange this equation as:

v=\frac{c}{n}

So from this we already see that if the index of refraction is lower, the speed of light in the medium will be higher, so one correct option is

B) waves speed up

Moreover, when light enters a medium bends according to Snell's Law:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1 ,n_2 are the index of refraction of the 1st and 2nd medium

\theta_1,\theta_2are the angles made by the incident ray and refracted ray with the normal to the interface

We can rewrite the equation as

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

So we see that if the index of refraction of the second medium is lower (n_2), then the ratio \frac{n_1}{n_2} is larger than 1, so the angle of refraction is larger than the angle of incidence:

\theta_2>\theta_1

This means that the wave will bend away from the normal. So the other correct option is

C) waves bend away from the normal

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Answer:

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