Given:
The magnitude of each charge is q1 = q2 = 1 C
The distance between them is r = 1 m
To find the force when distance is doubled.
Explanation:
The new distance is
The force can be calculated by the formula
Here, k is the constant whose value is
On substituting the values, the force will be
Answer:
a = -4/5 m/s^2
Explanation:
Acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
a = (20 m/s - 60 m/s) / 50 s
a = -40 m/s / 50 s
a = -4/5 m/s^2
hope this helps! <3
Limited resources: resources that take a long time to replenish
Example: coal, oil, nuclear gas
Non- limited resource: resources that are constantly being replenished
Example: soil, wind, water
Answer:
distance = 3 + 4 = 7 mi
displacement is √(3² + 4²) = 5 mi
Explanation:
A 300-kg bear grasping a vertical tree slides down at constant velocity. The friction force between the
tree and the bear is
