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Troyanec [42]
3 years ago
9

A massive block is being pulled along a horizontal frictionless surface by a constant horizontal force. The block must be ______

____. View Available Hint(s) A massive block is being pulled along a horizontal frictionless surface by a constant horizontal force. The block must be __________. continuously changing direction moving at constant velocity moving with a constant nonzero acceleration moving with continuously increasing acceleration
Physics
1 answer:
snow_tiger [21]3 years ago
4 0

Answer:

The body must be moving with a constant non zero acceleration.

Explanation:

Force produces acceleration on any mass it is applied on. The acceleration produced depends on the magnitude and direction of the force. For this block being dragged by a constant horizontal force, The body will undergo a constant non-zero acceleration that will steadily increase its velocity along the direction of the force.

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choli [55]

Answer:

1) on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.

2)If the angle is zero we see a bright light called undispersed light

For different angles we see the colors of the spectrum

3) must be able to see the well-collimated light emission source

Explanation:

1) A diffraction grating (diffraction grating) is a surface on which a series of indentations are drawn evenly spaced.

These crevices or lines are formed by copying a standard metal net when the plastic is melted and after hardening is carefully removed, or if the nets used are a copy of the master net.

The network can be of two types of transmission or reflection, in teaching work the most common is the transmission network, on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.

The number of lines per linear mm determines which range of the spectrum a common value can be observed to observe the range of viable light is 600 and 1200 lines per mm.

2) when looking through the diffraction grating what we can observe depends on the relative angle between the eye and the normal to the network.

If the angle is zero we see a bright light called undispersed light

For different angles we see the colors of the spectrum, if it is an incandescent lamp we see a continuum with all the colors in the visible range and if it is a gas lamp we see the characteristic emission lines of the gas.

3) Before mounting the grid on the spectrometer, we must be able to see the well-collimated light emission source, this means that it is clearly observed.

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3 0
4 years ago
Plzz helpppp meee!!!!
spin [16.1K]
A=f/m
A=900/425
A=2.18

To determine acceleration you divide the force by the mass.
4 0
3 years ago
Read 2 more answers
Q1) After applying a force of 1000 N an object of mass 2000 kg will achieve what<br>acceleration?​
wlad13 [49]

Answer:

F=mass x acceleration

1000= 2000 x a

a=1000/2000

a=1/2 m/sec^2

<em><u>mark it as brainliest!!!</u></em>

7 0
3 years ago
Read 2 more answers
The truck’s motor is creating 500 N of thrust, but air resistance is placing 500 N in the opposite direction
LenKa [72]
500-500=0 it has to be it
7 0
3 years ago
A hydraulic lift raises a 2 000-kg automobile when a 500-N force is applied to the smaller piston. If the smaller piston has an
stiv31 [10]

Answer:

The cross-sectional area of the larger piston is 392 cm²

Explanation:

Given;

output mass of the piston, m₀ = 2000 kg

input force of the piston, F₁ = 500 N

input area of the piston, A₁ = 10 cm² = 0.001 m²

The output force is given by;

F₀ = m₀g

F₀ = 2000 x 9.8

F₀ = 19600 N

The cross-sectional area of the larger piston or output area of the piston will be calculated by applying the following equations;

\frac{F_i}{A_i} = \frac{F_o}{A_o} \\\\A_o= \frac{F_o A_i}{F_i} \\\\A_o = \frac{19600*0.001}{500} \\\\A_o = 0.0392 \ m^2\\\\A_o = 392 \ cm^2

Therefore, the cross-sectional area of the larger piston is 392 cm²

3 0
4 years ago
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