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liubo4ka [24]
3 years ago
10

a dump truck travels 70mph for 3 hours, then for 20mph for another 2 hours in the same direction. what is the average speed the

car traveled?
Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

the average speed of the car is 170 mph.

Explanation:

Given;

initial speed, u = 70 mph

time of motion, t₁ = 3 hours

final speed, v = 20 mph

time of motion, t₂ = 2 hours

The average speed of the car is calculated as;

v' = \frac{70(3) - 20(2)}{3-2} \\\\v' = 170 \ mph

Therefore, the average speed of the car is 170 mph.

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A golfer hits a 42 g ball, which comes down on a tree root and bounces straight up with an initial speed of 15.6 m/s. Determine
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Answer:

12.2 m

Explanation:

Given:

v₀ = 15.6 m/s

v = 0 m/s

a = -10 m/s²

Find: Δy

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X: Use DC

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Jogging on hard surfaces with insufficiently padded shoes produces large forces in the feet and legs.
Step2247 [10]

Answer:

Part a)

F = 15600 N

Part b)

force is 21.2 times more than the weight of the person

Explanation:

Part a)

As it is given that the distance after which he stopped is given as

d = 1.50 cm

here finally it stops so final speed is given as

v_f = 0

initial speed is given as

v_i = 6 m/s

now by the equation of kinematics we know that

v_f^2 - v_i^2 = 2a d

0^2 - 6^2 = 2(a)(0.015)

a = -1200 m/s^2

Now the force on the leg is given as

F = ma

m = mass of leg = 13 kg

F = (13 kg)(-1200 m/s^2)

F = 15600 N

Part b)

Force due to weight of the object

F_g = Mg

here we know

M = 75.0 kg

F_g = 75(9.81)

F_g = 735.75 N

Now we know that the ratio of the weight with the force on leg is given as

\frac{F}{F_g} = \frac{15600}{735.75} = 21.2 N

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