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vaieri [72.5K]
3 years ago
14

Two boxes are at rest on a smooth, horizontal surface. The boxes are in contact with one another. If box 1 is pushed with a forc

e of magnitude F = 12.2 N , the contact force between the boxes is 8.90 N ; if, instead, box 2 is pushed with the force F, the contact force is 3.30 N . In either case, the boxes move together with an acceleration of 1.50 m/s2. What is the mass of box 1? What is the mass of box 2?
Physics
1 answer:
Maslowich3 years ago
8 0

Answer:

mass of box 1 = 2.20 kg

mass of box 2 = 5.93 kg

Explanation:

Let the mass of box 1 and box 2 is respectively

m_1 and m_2

so we will have

Force applied on box 1 then acceleration

a = \frac{F}{m_1 + m_2}

1.50 = \frac{12.2}{m_1 + m_2}

m_1 + m_2 = 8.13

Now we know that contact force between them in above case is given as

F_n = m_2a

8.90 = m_2(1.5)

m_2 = 5.93 kg

now we have

m_1 = 2.20 kg

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Answer:

1)4.7334J

2)225.4m/s

Explanation:

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H= Height of the bullet along circular arc= 10cm=0.1m

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We can write eqn(1) as

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If we make "v" subject of the formula we have

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1) We can now calculate the total energy of the system after collision as

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0.03u1=6.762

U1=225.4m/s

Hence, the initial velocity of the bullet is 225.4m/s

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