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Cloud [144]
3 years ago
6

How a scientist might use a graph of the

Chemistry
1 answer:
elena-s [515]3 years ago
8 0
Agora hemorrhage resqoio
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Nitric acid (HNO3) is used in the production of fertilizer, dyes, drugs, and explosives. Calculate the pH of a HNO3 solution hav
Alona [7]

Answer:

pH of HNO₃ having an hydrogen ion concentration of 0.71M is 0.149

Explanation:

HNO₃ (aqueous) ⇄ H⁺ + NO3⁻

The pH is defined as the negative log of the hydrogen ion concentration

pH = - log [H⁺]

From the question, the hydrogen ion concentration is given as 0.71M, therefore

pH = -log [0.71]

     = 0.149

3 0
3 years ago
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A celestial body is any natural (i.
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THE ANSWER IS I.ASTEROIDS   II.COMETS   III. METEOROIDS   IV. PLANETS PLZ MARK BRAINLISEST HOPE I HELPED THX

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3 years ago
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According to the principle of the conservation of mass the mass of the sodium sulfate was the following PLS HELP I NEED TO TURN
Annette [7]

Answer:

Explanation:

The Law of Conservation of Mass is defined and explained using examples of reacting mass calculations using the law are fully explained with worked out examples using the balanced symbol equation. The method involves reacting masses deduced from the balanced symbol equation.

5 0
3 years ago
What is the maximum mass of P2I4 that can be prepared from 8.80g of P4O6 and 12.37g of iodine according to the reaction:
Dvinal [7]
The balanced chemical reaction would be as follows:

<span>5P4O6 +8I2 ---> 4P2I4 +3P4O10

We are given the amount of reactants used for the reaction. We first need to determine the limiting reactant from the given amounts. We do as follows:

8.80 g P4O6 (1 mol / </span><span>219.88 g) = 0.04 mol P4O6
12.37 g I2 ( 1 mol / </span><span>253.809 g ) = 0.05 mol I2

Therefore, the limiting reactant is iodine since less it is being consumed completely in the reaction. We calculate the amount of P2I4 prepared as follows:

0.05 mol I2 ( 4 mol P2I4 / 8 mol I2 ) (</span><span>569.57 g / 1 mol) = 14.24 g P2I4</span>
8 0
3 years ago
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Natasha_Volkova [10]

Answer:

(C) through the atmosphere

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