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Mice21 [21]
3 years ago
6

What is a asteroid traveling rapidly called​

Physics
2 answers:
maksim [4K]3 years ago
6 0

Answer:

meteor

Explanation:

or some people call it a shooting star

SCORPION-xisa [38]3 years ago
4 0

Answer:

meteor

Explanation:

A asteroid stays still and a meteor goes fast

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Help me with the question b.​
Morgarella [4.7K]

Answer:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Liquid P - Q = 3840\,J, Liquid Q - Q = 5500\,J, Liquid R - Q = 7800\,J, Liquid S - Q = 2856\,J

Explanation:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Let suppose that heat transfer rates between liquids and surroundings are stable. The quantity of the heat released is determined by the following expression:

Q = m\cdot c\cdot (T_{r} - T_{f}) (1)

Where:

m - Mass of the liquid, in kilograms.

c - Specific heat capacity, in joules per kilogram-degree Celsius.

T_{r} - Initial temperature of the sample, in degrees Celsius.

T_{f} - Freezing point, in degrees Celsius.

Liquid P (m = 1\,kg, c = 160\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 6\,^{\circ}C)

Q = (1\,kg)\cdot \left(160\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 6\,^{\circ}C)

Q = 3840\,J

Liquid Q (m = 1\,kg, c = 220\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 5\,^{\circ}C)

Q = (1\,kg)\cdot \left(220\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 5\,^{\circ}C)

Q = 5500\,J

Liquid R (m = 1\,kg, c = 300\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 4\,^{\circ}C)

Q = (1\,kg)\cdot \left(300\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 4\,^{\circ}C)

Q = 7800\,J

Liquid S (m = 1\,kg, c = 102\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 2\,^{\circ}C)

Q = (1\,kg)\cdot \left(102\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 2\,^{\circ}C)

Q = 2856\,J

6 0
3 years ago
A straight segment of wire has a length of 25 cm and carries a current of 5A. If the wire is perpendicular to the magnetic field
Irina-Kira [14]

Answer:

The magnitude of the magnetic force acting on the conductor is 0.75 Newton

Explanation:

The parameters given in the question are;

The length of the straight segment of wire, L = 25 cm = 0.25 m

The current carried in the wire, I = 5 A

The orientation of the wire with the magnetic field = Perpendicular

The strength of the magnetic field in which the wire is located, B = 0.60 T

The magnetic force, 'F', is given by the following formula;

F = \underset{I}{\rightarrow }·L×\underset{B}{\rightarrow } = I·L·B·sin(θ)

Where;

\underset{I}{\rightarrow } = The current flowing, I

L = The length of the wire

\underset{B}{\rightarrow } = The magnetic field strength, B

θ = The angle of inclination of the conductor to the magnetic field

Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;

F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N

Therefore

The magnitude of the magnetic force, F = 0.75 N.

3 0
3 years ago
A baby and stroller have a total mass of
klio [65]
We know that the formula for the centripetal force is:

F = m·v² / r

Solving for v we get:

v = √(F · r / m)
   = √(36 N · 5.0 m / 20 kg)
   = 3.0 m/s

The stroller moves at a speed of <span>3.0 m/s.</span>
5 0
4 years ago
Read 2 more answers
A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples a
Allisa [31]

Answer:

B) 8 T.

Explanation:

For an ideal gas , the gas law that it follow is as follows

P₁V₁ / T₁ = P₂ V₂ /T₂

This law is followed by all the gases whether mono atomic or diatomic.

In this case following information are given

P₂ / P₁ = 3

V₂ / V₁ = 3

T₁ = T

T₂ = ?

From the gas law formula given , we have

T_2 =\frac{P_2\times V_2\times T_1}{P_1\times V_1}

V_2 = \frac{P_2}{P_1} \times\frac{V_2}{V_1}\times T

= 3 X 3 T

= 9 T

Change in temperature = 9T - T = 8 T.

7 0
3 years ago
The sound of frequency greater than 20,000 Hz is called ....
lapo4ka [179]

Answer:

ultra sound... follow me

3 0
4 years ago
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