Given :
A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.
To Find :
The coefficient of static friction between the box and the plane.
Solution :
Vertical component of force :
Horizontal component of force(Normal reaction) :
Since, box is on the verge of slipping :
Therefore, the coefficient of static friction between the box and the plane is 1.07.
Hence, this is the required solution.
1,000 grams = 1 kilogram
so 55 megagrams = 55,000 kilograms
100 cm = 1 meter
so 500 cm = 5 meters
Acceleration of gravity on Earth = 9.8 m/s²
Weight = (mass) x (gravity)
========================================
Work = increase in potential energy =
(weight) x (height) =
(mass) x (gravity) x (height) =
(55,000 kg) x (9.8 m/s²) x (5 m) =
2,695,000 joules .
Answer:
The minimum no. of turns is 
Explanation:
Given:
Magnetic field 
T
Frequency 
Hz
Area of turn 
Voltage 
V
From the formula of induced emf,
Where 
and 
So number of turn is,
Therefore, the minimum no. of turns is
Rarefactions are where you see the wave further apart. Where it's closer together, it's called a compression.
Answer:
objects falling at same rate.
Explanation:
ifif you neglect air resistance, objects following your Earth's surface or with the same approximate acceleration 9.8 meters per second squared (9.8 m/s^2, or g) due to Earth's gravity.
