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tino4ka555 [31]
2 years ago
5

How much heat is required to raise the temperature of 100 g of water from 5 degree celsius to 90 degree celsius?​

Physics
1 answer:
Scorpion4ik [409]2 years ago
8 0

Explanation:

1-How many moles of NazCOs are in 10.0 ml of a 2.0 M solution?

2-How many moles of NaCl are contained in 100.0 ml of a 0.20 M solution?

3- What weight (in grams) of H2SO4 would be needed to make 750.0 ml of

2.00 M solution?

4-What volume (in ml) of 18.0 M H2SO4 is needed to contain 2.45 g H2S04?

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According to Oxford Dictionaries, a spit take is an act of suddenly spitting out liquid one is drinking in response to something
Tasya [4]

Answer:

The pressure is p_1 = 4051.4 \ Pa

Explanation:

From the question we are told that

     The gauge pressure at the mouth is  p_1

     The radius of the column is  r_2 =  4 \ mm  =  0.004 \ m

    The speed of the liquid outside the body is  v_2 =  3.1 \ m/s

      The area of the column is  A_2

       The area inside the mouth A_1 = 10 A_2

Generally according to continuity equation

       v_1 A_1 =  v_2 A_2

=>       v_ 1 = v_2 *  \frac{A_2}{A_1}

=>      v_ 1 = 3.1 *  \frac{1}{10}

=>        v_ 1 = 0.31 \ m/s

So

      A_1 = 10A_2

=>   \pi * r_1^2 = 10(\pi * r_2^2)

=>   r_1 = 10 * r_2

substituting values

        r_1 = 10 * 0.004

        r_1 =0.04 \ m

Now the height of inside the mouth is  h_1 =  d =  2r_1 =  2* 0.04 =  0.08\ m

Now the height of the column is  h_2 =  d =  2r_2 =  2* 0.004 =  0.008\ m

Generally according to Bernoulli's  equation

        p_1 =  [\frac{1}{2}  \rho v_2^2 + h_2 \rho g +p_2] -[\frac{1}{2} \rho * v_1^2 + h_1 \rho g ]

Now  \rho =  1000 \ kg m^{-3} which is the density of water

        p_2 is the gauge pressure of the atmosphere which is  zero

 So

       p_1 =  [(0.5 * 1000 * (3.1)^2) +(0.008 * 1000 * 9.8) + 0]-

                                                  [(0.5 * 1000 * 0.31^2) + (0.08*1000 * 9.8)]                          

       p_1 = 4051.4 \ Pa

8 0
3 years ago
If the intensity of light that is incident on a piece of metal is increased, what else will be increased? Choose all that apply.
natka813 [3]

Answer:

explained

Explanation:

When the intensity of light is increased on a piece of metal only the number of electron ejected will increase because all other things independent of intensity of light.

Light below certain frequency will not cause any electron emission no matter how intense.

The intensity produces more electron but does not change the maximum kinetic energy of electrons.

Work function is independent of the intensity of light, because it is an intrinsic property of a material.

7 0
3 years ago
Which phrase most closely characterizes a person's sense of self?
vampirchik [111]
My guess would be choice D
7 0
3 years ago
I will mark as the brainliest answer<br><br>plz 8,9,10​
blagie [28]

Answer:

8.  acceleration = \dfrac{d(velocity)}{d(time)}  = 1 unit .

9. acceleration = \dfrac{d(velocity)}{d(time)}  = -1 unit.

10. acceleration = \dfrac{d(velocity)}{d(time)}  = 0 units.

Explanation:

8. i) acceleration = velocity / time

  ii) In this figure velocity = time

  iii) therefore acceleration = \dfrac{d(velocity)}{d(time)} = 1 unit .

9. i) acceleration = velocity / time

  ii) In this figure 4 = m + 5, therefore m = -1

     therefore velocity = (-0.5 \times time) + 5

  iii) therefore acceleration = \dfrac{d(velocity)}{d(time)}  = -1 units.

10.) velocity is constant at 2

     therefore acceleration = \dfrac{d(velocity)}{d(time)}  = 0 units

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3 years ago
A 2.0-kilogram cantaloupe rolling north at 4.0 meters per second collides head on with a 1.0-kilogram orange rolling south at 8.
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Answer:

Hi how are you doing today Jasmine

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