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2 years ago

The diagram below shows the path of a planet around a star.

Physics

1 answer:

Anit [1.1K]2 years ago

7 0

Answer:

Point C

Explanation:

Centripetal acceleration ac is inversely proportional to radius of orbit so it is greatest at point C.

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Which mixtures could be separated using evaporation? Check all that apply. fat in milk salt in ocean water mud in pond water but

salantis [7]

I would go with salt in ocean water as when you heat it and the water begins to evaporate it will leave the salt behind

Also water in mud as the water would evaporate and leave the mud residue behind

GOOD LUCK
BRAINLIEST IF HELPED

5 0

3 years ago

Read 2 more answers

1. A negatively charged rod is moved near the top of a positively charged electroscope. What

Xelga [282]

Answer:

A) Moves closer together

7 0

3 years ago

What type of fat may help lower the risk of heart disease

enyata [817]

Polyunsaturated fatty acids which is Omega-3 fatty acids.

8 0

3 years ago

What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe

Eduardwww [97]

Answer:

Final temperature, $T_f=21.85^{\circ}$

Explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature, $T_i=41^{\circ}C$

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver, $c=0.235\ J/g\ C$

To find,

Final temperature

Solution,

The expression for the specific heat is given by :

$Q=mc\Delta T$

$Q=mc(T_f-T_i)$

$T_f=\dfrac{-Q}{mc}+T_i$

$T_f=\dfrac{-18}{4\times 0.235}+41$

$T_f=21.85^{\circ}$

So, the final temperature of silver is 21.85 degrees Celsius.

5 0

3 years ago

Two balls are thrown against a wall. Ball 1 has a much higher speed than ball 2.

Sunny_sXe [5.5K]

Let both the balls have the same mass equals to m.

Let $v_1$ and $v_2$ be the speed of the ball1 and the ball2 respectively, such that

$v_1>v_2\;\cdots(i)$

Assuming that both the balls are at the same level with respect to the ground, so let h be the height from the ground.

The total energy of ball1= Kinetic energy of ball1 + Potential energy of ball1. The Kinetic energy of any object moving with speed, $v$ , is $\frac 12 m v^2$

and the potential energy is due to the change in height is $mgh$ [where $g$ is the acceleration due to gravity]

So, the total energy of ball1,

$=\frac 12 m v_1^2 + mgh\;\cdots(ii)$

and the total energy of ball1,

$=\frac 12 m v_2^2 + mgh\;\cdots(iii)$ .

Here, the potential energy for both the balls are the same, but the kinetic energy of the ball1 is higher the ball2 as the ball1 have the higher speed, refer equation (i)

So, $\frac 12 m v_1^2 >\frac 12 m v_2^2$

Now, from equations (ii) and (iii)

The total energy of ball1 hi higher than the total energy of ball2.

6 0

3 years ago