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2 years ago

The diagram below shows the path of a planet around a star.

Physics

1 answer:

Anit [1.1K]2 years ago

7 0

Answer:

Point C

Explanation:

Centripetal acceleration ac is inversely proportional to radius of orbit so it is greatest at point C.

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If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain u

zaharov [31]

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

6 0

3 years ago

Read 2 more answers

Dejamos caer un objeto desde lo alto de una torre y medimos el tiempo que tarda en llegar al suelo que resulta ser de 0,02 minut

Harman [31]

Answer: a) 11.76 m/s b) 7.056 m

Explanation:

The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

$V_{f}=V_{o}+at$ (1)

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (2)

Where:

$V_{f}$ Is the final velocity of the object

$V_{o}=0$ Is the initial velocity of the object (it was dropped)

$a=9.8 m/s^{2}$ is the acceleration due gravity

$d$ is the height of the tower

$t=0.02min=1.2 s$ is the time it takes to the object to reach the ground

b) Begining with (1):

$V_{f}=0+at$ (3)

$V_{f}=at=(9.8 m/s^{2})(1.2 s)$ (4)

$V_{f}=11.76 m/s$ (5) This is the final velocity of the object

a) Substituting (5) in (2):

$(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d$ (6)

Clearing $d$ :

$d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})}$ (7)

$d=7.056 m$ (8) This is the height of the tower

4 0

3 years ago

Pc13 is a compound used to make pesticides. A reaction requires that 96.7 kg of pc13 be raised from 31.7 degrees celcius to 69.2

siniylev [52]

Answer:

Energy required = 3169.34 Joules.

Explanation:

The quantity of energy (Q) required can be determined by;

Q = mcΔθ

Where: m is the mass, c is the specific heat and Δθ is the change in temperature.

But, m = 96.7 kg, c = 0.874 J/(kg $^{o} C$ ), $T_{2}$ = $69.2^{o}$ and $T_{1}$ = $31.7^{o}$ .

So that,

Q = mc( $T_{2}$ - $T_{1}$ )

= 96.7 x 0.874 x ( $69.2^{o}$ - $31.7^{o}$ )

= 96.7 x 0.874 x 37.5

= 3169.3425

Q = 3169.34

= 3.2 KJ

The amount of energy required is 3169.34 Joules.

8 0

3 years ago

Why does static friction have a maximum value

Naddik [55]

Answer:

If you push horizontally with a small force, static friction establishes an equal and opposite force that keeps the book at rest. As you push harder, the static friction force increases to match the force. Eventually maximum static friction force is exceeded and the book moves.

Explanation:

3 0

2 years ago

A gun is fired on a day when the speed of sound is 335 m/s and an echo is heard 0.75 seconds later. How far away is the object t

cricket20 [7]

Answer:

v= 335 m/s

2∆t= 0.75 s

∆x= v.∆t → ∆x= 335×½×0.75 = 125.625 m

8 0

3 years ago