Initial speed of Gazelle is along x direction and its value will be
also its initial height is given as
Part a)
now from kinematics along Y direction
as we know that
Part b)
distance moved horizontally
as we know that
now we will have
so it will lend at distance of 4 m.
Part c)
final velocity in vertical direction
so net speed will be
Answer:
u = 23.68 m/s
Explanation:
given,
mass of the car, m = 1900 Kg
Force exerted on the wall, F = 150,000 N
time of contact, t = 0.3 s
final speed of the car = 0 m/s
initial speed of the car = ?
we know,
Impulse is equal to change in momentum
J = m v- mu
J = 1900 x 0 - 1900 x (-u)
J = 1900 u
impulse is also equal to force into time
J = F x t
equating both equation of impulse
1900 u = F x t
1900 u = 150000 x 0.3
1900 u = 45000
u = 23.68 m/s
Speed of the car before collision is equal to 23.68 m/s
The only common property is that both of those things are comprised of H2O.
Answer:
a = - 0.3376 g's
Explanation:
The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s
It brakes and now comes to a stop in 3.6 s.
Thus final velocity = 0 m/s
Formula for acceleration is;
a = (v - u)/t
a = (0 - (164/13.77))/3.6
a = -3.308 m/s²
In terms of g's", where 1.00 g = 9.80 m/s², we have;
a = -3.308/9.8 g's
a = - 0.3376 g's
Answer:
the second one Test the rate of decay of specific elements in rock samples.
