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3 years ago

PLEASE HELP! NUMBER TWO PLEASE!! PLEASE SHOW ME HOW YOU DID IT! THANK YOU BUNCHES xoxo

Mathematics

1 answer:

aksik [14]3 years ago

3 0

Answer:

I will demonstrate the first two for you. The answer is 6, 30, 54, 78, 102.

The answer to the second question is -3, 21, 45, 63, 93.

Step-by-step explanation:

Pardon the messiness. I hope this clarifies how to do it from now on! If not, please let me know if you need more help! xoxo

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G(n)=n+1 f(n)-n^2-n find g(f(8))

bogdanovich [222]

Step-by-step explanation:

$g(f(8)) =( n ^{2} - n )+ 1 = 8 ^{2} - 8 + 1 = 64 + 9 = 73$

3 0

3 years ago

Suppose A,B and C are 2 ×2 matrices , E,F and G are 3 × 3 matrices, H and K are 2×3 matrices and L and M are 3×2 matrices. For e

Alekssandra [29.7K]

Answer:

a) 2x2 b)3x3 c) Not possible d) 2x3 e) 3x2 f) 3x3 g)Not possible h)3x2

Step-by-step explanation:

-> we can only add matrices with same size

-> we can only multiply when columns of first equal to rows of second

-> nxm multiplied by pxq gives nxq eg 3x2 mul 2x2 gives 3x2

-> addition and mul by const number dont change the size

So considering the above facts :-

a) AB+C = [(2x2)(2X2)]+(2x2)=(2x2)+(2x2)=2x2

b) 3GF =3[(3x3)(3x3)]=3(3x3)=3x3

c)CK+B= [(2x2)(2x3)]+(2x2)=(2x3)+(2x2) which is not possible (see point 1)

d)CK+H =as CK is (2x3) so (2x3)+(2x3)=(2x3)

e)EMC=[(3x3)(3x2)](2x2)=(3x2)(2x2)=3x3

f)GLH=[(3x3)(3x2)](2x3)=(3x2)(2x3)=3x3

g)HLG=[(2x3)(3x2)](3x3)=(2x2)(3x3)= not possible(see point 2)

h)2EL+5MB=2[(3x3)(3x2)]+5[(3x2)(2x2)]=(3x2)+(3x2)=3x2

8 0

3 years ago

I don’t understand this either

trasher [3.6K]

It is a part of slope form ( intercept

7 0

4 years ago

Read 2 more answers

Chanel is renting a digital video recorder from a cable supplier for a start up fee of $45 plus $5 per month. She has a budget o

Norma-Jean [14]

Fixed Cost = $45
Monthly Cost = $5

----------------------------------------
Define x:
----------------------------------------
Let x be the number of months she can rent.

----------------------------------------
Construct Inequality:
----------------------------------------
45 + 5x ≤ 250

----------------------------------------
Solve x :
----------------------------------------
45 + 5x ≤ 250
5x ≤ 250 - 45
5x ≤ 205
x≤ 41

--------------------------------------------------------------------------------
Answer: She can rent for a maximum of 41 months.
--------------------------------------------------------------------------------

5 0

4 years ago

Serena has attached a 10 inch ribbon to the corners of a frame to hang it on the wall. The frame 9 inches wide. How far above th

kherson [118]

Answer: The hook would be 2.2 inches (approximately) above the top of the frame

Step-by-step explanation: Please refer to the picture attached for further details.

The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (longest side) and AB and BC are the other two sides

5^2 = 4.5^2 + BC^2

25 = 20.25 + BC^2

Subtract 20.25 from both sides of the equation

4.75 = BC^2

Add the square root sign to both sides of the equation

2.1794 = BC

Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches

4 0

3 years ago