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3 years ago

7

A scientist finds a new life form. The life form is 2 meters tall. It makes its own food. It has tubes that carry food and water

through it. It reproduces by making seeds. Decide what kingdom this organism belongs to and explain how you classified it.

1 answer:

Nesterboy [21]3 years ago

3 0

I think it would belong in the Plantae Kingdom because of its reproduction through seeds. it would be tough to place it though without further examination.

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Basile [38]

Answer:

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3 years ago

7. A mother pushes her 9.5 kg baby in her 5kg baby carriage over the grass with a force of 110N @ an angle

jasenka [17]

Weight of the carriage $=(m+M)g =142.1\ N$

Normal force $=Fsin(\theta) + W = 197.1\ N$

Frictional force $=\mu N=27.59\ N$

Acceleration $=4.66\ m\ s^{-2}$

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

So Weight(W) $=(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)$

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with $F_x$ , force of $110\ N$ acting vertically downward.Both are downward and Normal is upward so Normal force $=Summation\ of\ both\ forces$

Normal force (N) $= Fsin(\theta)+W=110sin(30) + 142.1 =197.1\ N$

Frictional force (f) $=\mu N=0.14\times 197.1 =27.59\ N$

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that $F_y=Horizontal$ and $F_x=Vertical$ component of forces.

So Fnet = Fy(Horizontal) - f(friction) $= m\times a$

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So we have the weight of the carriage, normal force,frictional force and acceleration.

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3 years ago

How much pressure is on the bottom of a pot that holds 20N of soup? the surface area of the pot is 0.05m2

fomenos

Answer:

400

Explanation:

Formula used in solution:

$P = \frac{F}{A}$

$P - pressure,\: F - force,\: A - area$

The given information:

$F = 20N$

$A = 0.05m^{2}$

Solution

$P = \frac{F}{A} = \frac{20}{0.05} = 20 * 20 = 400$

Answer:

$Pressure = 400 \: Pascals$

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