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Juli2301 [7.4K]
3 years ago
13

Evaluation the expression: 7 + 2^3

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0

Answer:

try " 15"

Step-by-step explanation:

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Please help please please please
slamgirl [31]
If two events are dependent on each other you have to multiply the probability of the first event times the probability of the second event. 
first count all the marbles here there are 21
you are asked about picking two green marbles there are 7 out of the 21 total.
The first event would be 7/21
The second event would be 6/20 (since you didn't replace and you took out a green one)
now multiply your two fractions together:
and you get 1/10. 
8 0
3 years ago
What is the some need help????​
snow_tiger [21]

The sum formula for a geometric sequaence is:

sum(n) = a1(1-r^n)/1-r

Where n is the number of terms, a1 is the first term and r is the common ratio:

s(8) = 3(1-1/2^8) / (1-1/2)

s(8) = 3(1-1/256) / 1/2

s(8) = 2 253/256 / 1/2

s(8) = 765/128

The answer is C.

5 0
3 years ago
(4a) to the third power divided by (b-2) ; a=2 and b=4
Bingel [31]
(4(2)=8*8*8=512÷6=85.333333
(4-2)=2
8-2=6
8*2=16
8÷2=4
8+2=10
whichever operation it is

7 0
3 years ago
PLEASE ANSWER FAST 11 POINTS TO WHOEVER DOES WILL GET BRAIN LISTED PLEASE ANSWER I NEED THIS ASAP
dmitriy555 [2]

Answer: Yes, Raoul is correct because the initial value, also known as the y-intercept of function A is 0 and function B is 3.

Step-by-step explanation: The initial value is when x=0.

3 0
3 years ago
Read 2 more answers
A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling
lara31 [8.8K]

Answer:

a) weight  of the car = 2816,1 lbs

b) 2773 lbs

Step-by-step explanation:

The equilibrium force is 490 lbs. That force keep the car at rest, then

∑ Fy  =  0     and  ∑Fx  =  0

Forces acting on the car:

The external force   490 lbs

weight of the car   uknown

Normal force

sin∠10°  =  0,174

cos∠10° = 0.985

∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0

mg*0,174= 490

mg  =  490 / 0,174

mg = 2816,1 lbs

weight  of the car = 2816,1 lbs

The Normal force

mg*cos10° - N  =  0        2816,1 * 0,985 = N

N = 2773 lbs

Then equal force in magnitude and in opposite direction will car exets on the driveway

3 0
3 years ago
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