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S_A_V [24]
3 years ago
14

If an object is on top of a hill or in a position raised above the ground, it must have __________.

Chemistry
1 answer:
den301095 [7]3 years ago
6 0

Answer:

The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0.

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PLEASE HELP!!!!
coldgirl [10]

Answer:

1.2 liters.

Explanation:

Focus on the 4th digit: that's the ones column. The 3rd digit is the decimal place, just be sure to round up.

7 0
3 years ago
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
A balanced chemical equation is shown below
IrinaVladis [17]

Answer:

The answer is A.

Explanation:

C6H12O6 + 6O2 -> 6CO2 + 6H20

C6H12O6 + 6O2 -> 6CO2 + 6H20At the reactant side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

atoms, 12 hydrogen atoms and 18 oxygen atoms.At product side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

(In a balanced equation, the no. of atoms on the reactant side must be <em><u>e</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>l</u></em><em> </em>to the no. of atoms on the product side)

4 0
4 years ago
If a straight-chain hydrocarbon is a gas at room temperature, how many carbon atoms will it have?
Orlov [11]

The fewer the carbon atoms, the closer it is  to being a gas. The only one you have to check out is A which is hexane. You know that gasoline at the pumps has 8 carbons and its a liquid. So B and C are both not gases  because they are above 8.

C6 (hexane) is a liquid at room temperature not a gas.

The answer is D. If there is a gas present, it must be C3

6 0
3 years ago
Based on the wildfires that are occurring along the west coast in Washington,
aniked [119]

Answer:

Yes, wind and temperature are responsible for the spreading of fire.

Explanation:

Chemistry play a key role in the chemical reaction that is occurring in the wildfires because chemistry is the study of chemicals and in wildfires, the reaction of chemicals is responsible for the occurring and spreading of fire. Yes, wind currents and temperature has a great influence  on the fire spreading in the forests. The fire occurs in the forest is due to temperature while its spreading happens due to wind. Placing water on the fire does not help extinguish the fire because the the fire particles can be transmitted for a fair distance by wind.

4 0
4 years ago
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