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AleksAgata [21]
3 years ago
11

A hydrogen atom in an excited state absorbs a photon of wavelength 411 nm. What were the initial and final states of the hydroge

n atom?
Physics
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

The initial and final states of the hydrogen atom were n=2 and n=6 respectively.

Explanation:

We must first obtain the energy of the photon;

E= hc/λ

where;

h= Plank's constant = 6.6 * 10^-34 JS

c= speed of light = 3* 10^8 m/s

λ = wavelength of light= 411 nm = 411* 10^-9 m

Substituting values;

E = 6.6 * 10^-34 * 3* 10^8 / 411* 10^-9

E = 4.8 * 10^-19 J or 3.0 eV

But ;

En = 13.6/n^2

So E = En final - En initial

3.0  = -13.6(1/n^2final - 1/n^2initial)

If we substitute n^2final = 6 and n^2 initial = 2 then the RHS becomes approximately equal to the LHS

Therefore the initial and final states of the hydrogen atom were n=2 and n=6 respectively.

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An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
poizon [28]

Answer:

The value is A  =  0.014 \  m

Explanation:

From the question we are told that

    The mass of the object is  m  =  2.0 \  kg

    The unstressed length of the string is  l  =  0.08 \  m

    The length of the spring when it is  at equilibrium is  l_e = 5.9 \  cm  =  0.059 \  m

      The initial speed (maximum speed)of the spring when given a downward blow v  =  0.30 \  m/s

Generally the maximum speed  of the spring  is mathematically represented as

           u =  A *  w

Here A is maximum height above the floor (i.e the maximum amplitude)

            and w is the angular frequency which is mathematically represented as

       w = \sqrt{\frac{k}{m} }

So

        u =  A *   \sqrt{\frac{k}{m} }

=>      A  =  u *   \sqrt{\frac{m}{k} }

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

           b  =  l -l_e

=>         b  = 0.08 - 0.05 9

=>         b  = 0.021 \  m

Generally at equilibrium position the net force acting on the spring is  

            k *  b  -  mg  =  0

=>         k *  0.021   -   2 * 9.8  =  0

=>        k =  933 \  N/m

So

            A  =  0.30  *   \sqrt{\frac{2}{933} }

=>          A  =  0.014 \  m

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3 years ago
Which of the following is a form of pollution created when vehicle exhaust interacts with sunlight?
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8 0
2 years ago
A train has a constant velocity of 2 m/s east. What is the magnitude of the horizontal acceleration of the train?
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"Constant velocity" is practically a definition for zero acceleration.
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A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with
Ray Of Light [21]

Answer:

See below

Explanation:

Vertical position = 45 +  20 sin (30) t  - 4.9 t^2

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      it will <u>also</u> still have horizontal velocity =  20 cos 30 = 17.32 m/s

        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

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