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Sav [38]
3 years ago
5

Which of these is a chemical control used to help control invasive species?

Physics
1 answer:
astraxan [27]3 years ago
4 0

Answer:

a

Explanation:

Using fences.................................

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The period of a carrier wave is T=0.01 seconds. Determine the frequency and wavelength of the carrier wave. a. f=10 Hz, λ=3E8 me
makvit [3.9K]

Explanation:

It is given that,

The period of the carrier wave, T = 0.01 s

Let f and \lambda are frequency and the wavelength of the wave respectively. The relationship between the time period and the frequency is given by :

f=\dfrac{1}{T}

f=\dfrac{1}{0.01}

f = 100 Hz

The wavelength of a wave is given by :

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8}{100}

\lambda=3\times 10^6\ m

So, the  frequency and wavelength of the carrier wave are 100 Hz and 3\times 10^6\ m respectively. Hence, the correct option is (c).

6 0
3 years ago
Un movil viaja a 40km/h y comienza a reducir su velocidad a partir del instante t=0. Al cabo de 6 segundo se detiene completamen
aleksklad [387]

Answer:

1,85 m / s²

Explanation:

De la pregunta anterior, se obtuvieron los siguientes datos:

Velocidad inicial (u) = 40 km / h

Hora inicial (t₁) = 0

Tiempo final (t₂) = 6 s

Velocidad final (v) = 0

Aceleración (a) =?

A continuación, convertiremos 40 km / ha m / s. Esto se puede obtener de la siguiente manera:

1 km / h = 0,2778 m / s

Por lo tanto,

40 km / h = 40 km / h × 0,2778 m / s / 1 km / h

40 km / h = 11,11 m / s

Por tanto, 40 km / h equivalen a 11,11 m / s.

Finalmente, determinaremos la aceleración del móvil durante el período en el que desaceleró. Esto se puede obtener de la siguiente manera:

Velocidad inicial (u) = 11,11 m / s

Hora inicial (t₁) = 0

Tiempo final (t₂) = 6 s

Velocidad final (v) = 0

Aceleración (a) =?

a = (v - u) / (t₂ - t₁)

a = (0 - 11,11) / (6 - 0)

a = - 11,11 / 6

a = –1,85 m / s²

Por tanto, la aceleración del móvil durante el período en el que se ralentizó es de –1,85 m / s²

6 0
3 years ago
A block whose weight is 45.8 N rests on a horizontal table. A horizontal force of 36.6 N is applied to the block. The coefficien
Liula [17]

Answer:

Yes it will move and a= 4.19m/s^2

Explanation:

In order for the box to move it needs to overcome the maximum static friction force

Max Static Friction = μFn(normal force)

plug in givens

Max Static friction = 31.9226

Since 36.6>31.9226, the box will move

Mass= Wieght/g which is 45.8/9.8= 4.67kg

Fnet = Fapp-Fk

= 36.6-16.9918

=19.6082

=ma

Solve for a=4.19m/s^2

7 0
3 years ago
Which of these would not contribute to a global increase in temperature?
Katyanochek1 [597]

Answer:

planting trees - increasing the amount of animal life on earth

Explanation:

from all the other options given, all except planting trees will increase global temperature.

1. deforestation: this removes vegetative cover and the amount of oxygen in the atmosphere.

2. increasing the use of gasoline burning vehicles: burning gasoline produces carbon dioxide which is a green house gas which traps heat in the atmosphere and causes global warming

3. increasing the industrial release of carbon dioxide: carbon dioxide is released when gasoline is burned in industries, this in-turn causes global warming.

Trees produces oxygen and sucks in carbon dioxide which causes global warming. more trees mean more oxygen and less carbon dioxide which translates to less global increase in temperature

6 0
3 years ago
What are the top three osha cited ladder violations
bonufazy [111]

Answer:

Explanation:

1. FALL PROTECTION-GENERAL REQUIREMENTS (29 CFR 1926.501) 6,010 VIOLATIONS

2. HAZARD COMMUNICATION (29 CFR 1910.1200). 3,671

3. SCAFFOLDING (29 CFR 1926.451). 2,813

6 0
3 years ago
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