All categories

3 years ago

PLEASE HELP! (8.01 MC)

1 answer:

7 0

Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.

You might be interested in

What does frequency describe? A.distance from crest to crest or from trough to trough on a wave B.Number of waves that pass a gi

Shalnov [3]

Answer:

B.Number of waves that pass a given point in a given time.

3 0

3 years ago

Fill in the coefficients that will balance the following reaction:

vfiekz [6]

6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O

Explanation:

Given equation;

NaC₂H₃O₂ + Fe₂O₃ → Fe(C₂H₃O₂)₃ + Na₂O

To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.

Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.

aNaC₂H₃O₂ + bFe₂O₃ → cFe(C₂H₃O₂)₃ + dNa₂O

a, b, c and d are the coefficients that will balance the equation.

conserving Na; a = 2d

C: 2a = 6c

H: 3a = 9c

O; 2a + 3b = 6c + d

Fe: 2b = c

let a = 1

solving:

2a = 6c

2(1) = 6c

c = $\frac{2}{6} = \frac{1}{3}$

2b = c

b = $\frac{1}{2} x \frac{1}{3}$ = $\frac{1}{6}$

d = 2a + 3b - 6c = 2(1 ) + (3 x $\frac{1}{6}$ ) - (6 x $\frac{1}{3}$ ) = $\frac{1}{2}$

Now multiply through by 6

a = 6, b = 1, c = 2 and d = 3

6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O

learn more:

Balanced equation brainly.com/question/9325293

#learnwithBrainly

6 0

3 years ago

Charlie is balancing an equation. She has identified the atoms and counted the number of each in the reactants and products. Wha

Alecsey [184]

The answer to your question is Coefficients.

*Hope this helps you! Feel free to message me if you have any further questions. Have a nice day! :)*

8 0

3 years ago

Read 2 more answers

Is a Animal and Plant cell living

Mila [183]

Yes Animal and plant are cell living

7 0

3 years ago

A chemist wishing to do an experiment requiring 47-Ca2+ (half-life = 4.5 days) needs 5.0 μg of the nuclide. What mass of 47-CaCO

NARA [144]

Answer:

5.8μg

Explanation:

According to the rate or decay law:

N/N₀ = exp(-λt)------------------------------- (1)

Where N = Current quantity, μg

N₀ = Original quantity, μg

λ= Decay constant day⁻¹

t = time in days

Since the half life is 4.5 days, we can calculate the λ from (1) by substituting N/N₀ = 0.5

0.5 = exp (-4.5λ)

ln 0.5 = -4.5λ

-0.6931 = -4.5λ

λ = -0.6931 /-4.5

=0.1540 day⁻¹

Substituting into (1) we have :

N/N₀ = exp(-0.154t)----------------------------- (2)

To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:

N = 5.0 μg

N₀ = Unknown

t = 1 day

Substituting into (2) we have

[5/N₀] = exp (-0.154 x 1)

5/N₀ = 0.8572

N₀ = 5/0.8572

= 5.8329μg

≈ 5.8μg

The Chemist must order 5.8μg of 47-CaCO3

6 0

3 years ago