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Arada [10]
3 years ago
6

PLEASE HELP! (8.01 MC)

Chemistry
1 answer:
Maslowich3 years ago
7 0
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.
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A student wants to remove the salt from a mixture of sand and salt in order to get only pure sand. He adds water to the mixture.
raketka [301]

Answer:

Here is one way: Add water to the mixture. Only the sugar dissolves. This is a physical change.

Explanation:

The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.

5 0
3 years ago
Read 2 more answers
Several properties of water are shown. Classify each property as a physical property or a chemical property.
34kurt

Chemical property:

  • Can be split into hydrogen and oxygen
  • Reacts with certain metals

Physical property:

  • Is liquid at room temperature
  • Has a density of 1.0 g/cm³
7 0
2 years ago
You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, p
Elenna [48]

Answer:

  • <u>1.29 mol</u>

Explanation:

This is a direct application of the equation for ideal gases.

  • PV=nRT

Where:

  • P = pressure = 1.25 atm
  • V = volume = 25.2 liter
  • R = Universal constant of gases = 0.08206 atm-liter/K-mol
  • T = absolute temperature = 25.0ºC = 25 + 273.15 K = 298.15 K
  • n = number of moles

Solving for n:

  • n=\frac{PV}{RT}

Substituting:

n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol

8 0
3 years ago
How many moles of water are there in 1.000 l at stp? assume the density of water is 1000 kg/m3?
EastWind [94]
Assume 1 liter = 1 kilogram of water = 1000 grams of water.

Part A)
MW of hydrogen is 1.008g/mol, and oxygen is 16.00g/mol.

Find the MW of water by
2*(1.008) + (16.00) = 18.016g/mol.

Convert 1000g H2O to moles :

(1000g H2O)*(1mol H2O / 18.016g H2O) = 55.51 mol

Part B)
Using the answer from part A and Avogadro's number:

(55.51mol)*(6.022*10^23) =

3.343*10^25 molecules.
Hope this is helpful
7 0
3 years ago
We consider a spherical air bubble rising through a water tank. The pressurepinside the bubble isequal to its surrounding pressu
DENIUS [597]

The answer is a change in internal energy causes work to be done and heat to flow into the system.  

<u>Explanation:</u>

Boyle's law says, PV=RT

  • Here P represents the pressure, V represents the volume and T represents the temperature. R is a constant. The volume of an ideal gas is inversely proportional to its pressure if the temperature is constant.
  • When a bubble is present in deep water it has water pressure and atmospheric pressure. Then the Volume increases when water pressure raises which is proportional to the depth reduces.
  • But we should not finalize the volume of the bubble will be four-time as great as at the top than the bottom.  if the bottom of the lake is at four atmospheres, the temperature will not be equal to the top.
  • If the bubble travels from the bottom to the top or vice-versa, it's going to lose or gain heat in a way that must be quite hard to measure.
8 0
4 years ago
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