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RideAnS [48]
3 years ago
8

Which of the following numbers is correctly rounded to three significant figures, as shown in brackets?​

Chemistry
1 answer:
vodomira [7]3 years ago
4 0

Answer:

D is correctly rounded to three significant figures.

Explanation:

A is incorrect because although it has 3 significant figures, it is rounded incorrectly. The correct answer would be 12,600.

B is incorrect because is rounded to 4 significant figures instead of three.

C is also incorrect because is rounded to 4 significant figures instead of three.

D is correctly rounded to three significant figures.

E is also incorrect because is rounded to 4 significant figures instead of three.

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How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
Elements
Snezhnost [94]

Answer:

elements are composed of

electrons with a little mass and negative charge

protons with mass and positive charge

neutrons with mass and no charge

isotopes same number of protons, different in neutrons

share me the other part of the photo to complete!!!

7 0
3 years ago
Which of the following sets of empirical formula, molar mass, and molecular formula is correct?
lutik1710 [3]

Answer:

CH4N, 90g, C3H12N3

Explanation:

3 0
3 years ago
What is the SI unit used to measure weight?
stepladder [879]

Answer:

The si unit used to measure weight is kilogram /kg

7 0
2 years ago
Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)
Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s)   (1)

We can write the above reaction in <u>two reactions</u>, one for oxidation and the other for reduction:

  • Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻   (2)

  • Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s)    (3)

We can see that Li⁰ is oxidizing to Li⁺ (by <u>losing</u> one electron) in the lithium acetate (<em>reaction 2</em>) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by <u>gaining</u> two <em>electrons</em>) (<em>reaction 3</em>).  

We must remember that the reducing agent is the one that will be oxidized by <u>reducing another element</u> and that the oxidizing agent is the one that will be reduced by <u>oxidizing another species</u>.

In reaction (1), the<em> reducing agent</em> is <em>Li</em> (it is oxidizing to Li⁺), and the <em>oxidizing agent </em>is<em> Fe(CH₃COO)₂</em> (it is reducing to Fe⁰).  

Therefore, the reducing agent in reaction (1) is lithium (Li).  

 

Learn more here:

  • brainly.com/question/10547418?referrer=searchResults
  • brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

3 0
2 years ago
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