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How much space do 2x10 22 copper pennies take up

soldi70 [24.7K]

Answer:

40+22=

Explanation:

62

3 0

3 years ago

Answer A B C and D please for my chemistry hw

r-ruslan [8.4K]

Answer: The equations are provided below.

Explanation:

Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.

Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.

For A:

Water decomposes in the direct current to form hydrogen and oxygen.

Skeleton Equation: $H_2O(l)\rightarrow H_2(g)+O_2(g)$

Balanced Equation: $2H_2O(l)\rightarrow 2H_2(g)+O_2(g)$

For B:

Mercury (II) oxide decomposes in heat to form mercury, oxygen.

Skeleton Equation: $HgO(s)\rightarrow Hg+O_2$

Balanced Equation: $2HgO(s)\rightarrow 2Hg+O_2$

For C:

Calcium carbonate when heated forms calcium oxide and carbon dioxide.

Skeleton Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

Balanced Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

For D:

Group 2 hydroxides, when heated forms oxide and water vapor.

Skeleton Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

Balanced Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

3 0

3 years ago

What was used to build the phylogenetic

Gnom [1K]

A phylogenetic tree may be built using morphological (body shape), biochemical, behavioral, or molecular features of species or other groups. In building a tree, we organize species into nested groups based on shared derived traits (traits different from those of the group's ancestor).

8 0

3 years ago

What was the key design change for hfc-134a a/c systems versus CFC 12 a/c systems

BabaBlast [244]

Answer is: key design change for HFC-134a A/C systems versus CFC-12 A/C systems was quick couple service fitting and that design reduce venting and mixing of refrigerants during service.

Level of contamination is also reduced and the emission of refrigerants and greenhouse gases (sulfur dioxide, carbon dioxide) is also reduced.

6 0

3 years ago

A sample of gas occupies 7.80 liters at 425°C? What will be the volume of the gas at 35°C if the pressure does not change?

balandron [24]

From ideal gas equation PV = nRT, V/T = nR/P ==> V/T = constant. Therefore V1/T1 = V2/T2 ==> 7.8/698 = V2/308. V = 3.44L {TEMPERATURE IN KELVIN = 273 + 425 AND 35 = 698 AND 308}

4 0

2 years ago