Answer:
The answer to your question is:
a) 3.87 mol of CO2
b) 14.63 mol of O2
Explanation:
2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(g)
a)
CO2 = ?
Butane 0.968 moles
From the balance equation 2 moles of butane ---------- 8 moles of CO2
0.968 moles of butane ------ x
x = (0.968 x 8) / 2
x = 3.87 moles of CO2
b)
moles O2 = ?
butane = 2.25 mol
From the balance equation
2 moles of butane ---------- 13 mol O2
2.25 mol ---------- x
x = (2.25 x 13) / 2
x = 14.63 mol of O2
When sodium chloride is molten:
NaCl ------> Na⁺ +Cl⁻
Anod (+) | Cathode (-)
2Cl⁻-2e⁻ ---> Cl2(gas) | Na⁺ + e⁻ -----> Na⁰(s)
I would go with C hope this helps
The pH meter can only be used to differentiate between weak and strong acids providing that the concentrations are known. However, it is convenient to determine the concentration of an acid (or base) by titration.
The conversation rate is c+273=k
