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Mumz [18]
3 years ago
15

What structures are part of the body's first line of defense against pathogens

Chemistry
1 answer:
marshall27 [118]3 years ago
5 0

Answer:

It would be the innate immune system or just the immune system

Explanation:

:)

You might be interested in
Explain why the ionization energy to remove a second electron from potassium is higher than the ionization energy to remove four
never [62]

Explanation:

It is more difficult to remove electrons from the second shell or energy level because of the imbalance between the positive nuclear charge and the remaining electrons.

  • The amount of energy required to remove electrons in ground state of an atom is the ionization energy.
  • The first ionization energy is the energy needed to remove the most loosely bound electron of an atom in the gas phase in ground state.
  • The second energy has a greater nuclear pull as it is closer to the nucleus.
  • Both potassium and silicon have the same number of energy levels.
6 0
3 years ago
CF4 + Br2 CBr4 + F2
luda_lava [24]

Answer:

Answers are in the explanation

Explanation:

Based on the reaction:

CF₄ + 2Br₂ → CBr₄ + 2F₂

The mole ratio of CF₄ is:

CF₄:Br₂ = 1:2

CF₄:CBr₄ = 1:1

CF₄:F₂ = 1:2

<em>Moles F2:</em>

Molar mass CF₄: 88.0g/mol

57.0g * (1mol / 88.0g) = 0.6477 moles CF₄ * (2mol F₂ / 1mol CBr₄) =

<h3>1.30 moles F₂</h3><h3 />

<em>Mass Br2:</em>

Molar mass CBr₄: 331.63g/mol

250.0g * (1mol / 331.63g) = 0.7539 moles CBr₄ * (2mol Br₂ / 1mol CF₄) =

1.51 moles Br₂ * (159.808g / mol) =

<h3>241g Br2</h3><h3 /><h3 />

<em>Moles F2:</em>

4.8 moles CF₄ * (2mol F₂ / 1mol CF₄) =

<h3>9.6 moles F₂</h3><h3 />

<em />

5 0
3 years ago
3. If 90.0 grams of barium chloride react with sulfuric acid, how many
PtichkaEL [24]

Answer:

The answer to your question is 100.8 g

Explanation:

Data

  mass of Barium chloride = 90 g

  mass of Barium sulfate = ?

Balanced chemical reaction

    BaCl₂  +  H₂SO₄   ⇒    BaSO₄  +  2HCl

Process

1.- Calculate the molar mass of BaCl₂ and BaSO₄

BaCl₂ = 137.3 + (2 x 35.5) = 208.3g

BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g

2.- Use proportions to find the mass of BaSO₄

              208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄

                90 g of BaCl₂    ---------------------   x

                              x = (90 x 233.3) / 208.3

                              x = 20997/ 208.3

                              x = 100.8 g

3.- Conclusion

There will be produced 100.8 g of BaSO₄          

4 0
3 years ago
What mass of water is required to react completely with 157.35 g CO2? (Molar mass of H2O = 18.02 g/mol; molar mass of CO2 = 44.0
Ghella [55]

You must use 64.43 g H₂O.

<em>Balanced chemical equation</em>: H₂O + CO₂ → H₂CO₃

<em>Moles of CO₂</em> = 157.35 g CO₂ × (1 mol CO₂/44.01 g CO₂) = 3.5753 mol CO₂

<em>Moles of H₂O</em> = 3.5753 mol CO₂ × (1 mol H₂O/1 mol CO₂) = 3.5753 mol Fe

<em>Mass of H₂O</em> = 3.5753 mol H₂O × (18.02 g H₂O /1 mol H₂O) = 64.43 g H₂O

6 0
3 years ago
Read 2 more answers
Aluminum has a density of 2.70 g/cm3. what would be the mass of a sample whose volume is 10.0 cm3?
anastassius [24]
Hey there!

Density = 2.70 g/cm³

Volume = 10.0 cm³

Therefore:

Mass = density *  volume

Mass = 2.70 * 10.0

Mass = 27.0 g
3 0
3 years ago
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