Here is a picture of my work. It's easier than typing it out!
The zeroth law of thermodynamics states that if two thermodynamic systems each are in thermal equilibrium with a third, then they are in thermal equilibrium with each other.
Given that,
Angle = 30°
Initial velocity = 15 m/s
We need to calculate the time of flight
Using formula of time of flight
Where, u = initial velocity
g = acceleration due to gravity
Put the value into the formula
We need to calculate the final velocity of the ball
Using equation of motion
Hence, The final velocity of the ball is 29.7 m/s.
1. The property of a conductor by virtue of which it posses the flow of electric current through it is called resistance.
2. The resistance of a conductor depends on the cross sectional area of the conductor and it's resistivity.
3.This id due to the fact that the resistance of a wire is inversely proportional to the square of its diameter.
4.Due to at high temperatures , the alloy donot oxidize. Alloy doesn't melt readily and get deformed.
A delightful problem !
I'm pretty sure that what we need here is the speeds, not the velocities,
and that's the way I'm going to do it.
Regular speed is (distance covered) divided by (time to cover the distance) .
Angular speed is very much the same.
It's
(angle turned) divided by (time to turn the angle) .
<u>Earth's orbit around the sun</u>:
..... Once per year.
..... Roughly 360° in 365 days ..... <em>almost exactly 1° per day</em>.
Let's see what it is more accurately:
(360°) / (<span>365.25636<span> days) = 0.985609° per day.
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<u>Earth's rotation on its axis</u>:
..... Once per "day".
..... Roughly 360° in 24 hours ..... <em>almost exactly 15° per hour</em>.
This one is slightly trickier to do more accurately, because a day is
not necessarily 24 hours. It depends on what you call 1 day.
-- If you say the day is the period of time between when the sun is
highest in the sky, then that averages out to 24 hours in the course
of a year.
-- If you say that the day is the period of time it takes for a star
to reach the same point in the sky tomorrow night, then that's </span></span>
23 hours, 56 minutes, 4.09 seconds .
Using this to calculate the angular speed of rotation, you get
(360°) / (23h 56m 4.09s) = 15.041° per hour