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3 years ago

Differences differences between gravity and acceleration due to gravity

Physics

1 answer:

Nina [5.8K]3 years ago

4 0

Look at this table. Accleration of gravity means gravitational constant.

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A jet lands on an aircraft carrier at 140 mi/h. What is its acceleration if it stops in 2.0 seconds?

sergejj [24]

Answer:

Acceleration, $a=-31.29\ m/s^2$

Explanation:

It is given that,

Initial speed of the aircraft, u = 140 mi/h = 62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{0-62.58}{2}$

$a=-31.29\ m/s^2$

So, the acceleration of the aircraft is $31.29\ m/s^2$ and the car is decelerating. Hence, this is the required solution.

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3 years ago

What three ways are molecules used when they are stored for energy?

Dafna11 [192]

Speed, agility, physical activity

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2 years ago

What causes the apparent motions of stars across the sky each night

densk [106]

Answer:

Explanation:

for the motion every night, it is because the Earth spins on its axis.

for the changes over a year, this is because the Earth rotates around the sun.

for the changes over hundreds, thousands or millions of years, this is because the whole solar system (including the Earth, of course) rotates with all the other stars in our galaxy around the center of the galaxy. and each star system has its own orbit (similar to the planets in our solar system).

it is very rare to see objects outside of our galaxy without a telescope, but they change too over a long period of time, because our galaxy not only rotates by also moves through the universe, and these other objects move on their own too.

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2 years ago

Studen

Vesna [10]

Complete Question

A football coach walks 18 meters westward, then 12 meters eastward, then 28 meters westward, and finally 14 meters eastward.

From this motion what is the distance covered

What is the magnitude and direction of the displacement

Answer:

$D = 72 \ m$

Magnitude

$d = - 20 \ m$

Direction

West

Explanation:

From the question we are told that

The first distance covered westward is $d_w_1 = 18 \ m /tex] The first distance covered eastward is [tex]d_e1 = 12 \ m /tex] The second distance covered westward is [tex]d_w_2 = 28 \ m /tex] The second distance covered eastward is [tex]d_e2 = 14 \ m /tex] Generally the distance covered is mathematically represented as [tex]D = d_w1 + d_w2 + d_e1 + d_e2$

=> $D = 18 + 28 + 12 + 14$

=> $D = 72 \ m$

For the second question eastward is in the direction of the positive x-axis so it would be positive and westward is in the direction of the negative x-axis so it would be negative

The magnitude of the displacement is

$d = -d_w1 -d_w2 + d_e1 + d_e2$