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Anestetic [448]
3 years ago
9

A diamond is underwater; A light ray enters one face of the diamond, then travels at an angle of 30 degrees with respect to the

normal. What was the ray's angle of incidence on the diamond? The index of refraction of water is nwater=1.33, and the index of refraction of diamond is ndiamond=2.42. Finally, apply Snell's law and find the ray's angle of incidence θ1 on the diamond.
Physics
1 answer:
otez555 [7]3 years ago
4 0
According to snells law 

<span>n1 sin theta1 = n2 sin theta2
</span>n1  = 1.333 (water)
<span>n2  = 2.42 (diamond)</span>
 it is given that theta =30 degrees so 
by putting the values we have 

<span>1.333 sin theta = 2.42 sin 30 </span>

<span>sin theta = (2.42/1.333) *0.5 =65.2 degree
</span>so our conclusion is 

<span>the ray's angle of incidence θ1 on the diamond</span> = 65.2 degree.
hope this helps
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