While making chicken soup for his family one evening, Luis added the amount of salt the recipe called for. After tasting the sou
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Answer:
0.9483 grams of manganese dioxide should be added to excess HCl.
Explanation:
Pressure of the chlorine gas = P = 795 Torr = 1.046 atm (1 atm = 760 Torr)
Volume of the chlorine gas = V = 255 ml = 0.255 L
Temperature of the chlorine gas = T = 25°C= 298.15 K
Moles of chlorine gas = n
Using ideal gas equation:
PV = nRT
n = 0.01090 mol
According to reaction , 1 mole of chlorine gas is obtained from 1 mole of manganese dioxide.
Then 0.01090 moles of chlorine gas will be obtained from:
manganese dioxide
Mass of 0.01090 moles of manganese dioxide:
0.01090 mol × 87 g/mol = 0.9483 g
<h3>Answer:</h3>
2 M
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Unit 0</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Aqueous Solutions</u>
- Molarity = moles of solute / liters of solution
<u>Step 1: Define</u>
36.7 g CaF₂
300 mL H₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
Molar Mass of F - 19.00 g/mol
Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol
1000 mL = 1 L
<u>Step 3: Convert</u>
<em>Solute</em>
- Set up:
- Multiply:
<em>Solution</em>
- Set up:
- Multiply:
<u>Step 4: Find Molarity</u>
- Substitute [M]:
- Divide:
<u>Step 5: Check</u>
<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>
1.56677 M ≈ 2 M