What is the voltage required to push 0.5 amps of current through a 10 ohm resistor?

Chemistry

1 answer:

nadya68 [22]3 years ago

6 0

V = IR
I = 0.5 amps
R = 10 ohms

So, V = 0.5 • 10 = 5V

You might be interested in

Which is a polar molecule?

Sloan [31]

A polar molecule is when the arrangement of the atoms in molecules are unequal where one end of the molecule has a positive charge while the other end has a negative charge. Examples of a polar molecule are water, ammonia, hydrogen sulfide and sulfur dioxide. The opposite is called a nonpolar molecule.

5 0

3 years ago

A major difference between deep ocean currents and surface currents is that deep ocean currents _____.

Andrew [12]

The correct answer is c

8 0

3 years ago

Read 2 more answers

Determina el numero de masa para el paladio en la siguiente tabla:*

Damm [24]

The concept of atomic masses we can find that the correct answer is:

c) 101

The atomic mass or mass number of an element is the sum of its protons plus the neutrons that are in the atomic nucleus, the electrons are not taken into account because they have a mass much lower than the masses of protons and neutrons.

In the table they indicate that there are 46 protons and 55 neutrons, therefore

M = #_ {protons} + #_ {neutrons}

M = 46 +55

M = 101

In conclusion using the concept of atomic masses we find that the correct answer is:

c) 101

Learn more about atomic mass here:

brainly.com/question/1317964

5 0

3 years ago

Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac

GalinKa [24]

<h2>a) The rate at which $NO_2$ is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen $O_2$ is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$ = 0.066 M/s