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uysha [10]
3 years ago
13

I need help please. The top question.

Chemistry
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

i cant see anything lol sorry

Explanation:

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How many moles of NF3 are present in a sample that contains 8.02 moles of a Fluorine atom
Ad libitum [116K]

Hey there!

The sample of NF₃ contains 8.02 moles fluorine atoms.

There are 3 fluorine atoms in each molecule, so there will be 1/3 of the moles of fluorine.

8.02 / 3 = 2.67

There are 2.67 moles of NF₃ in a sample that contains 8.02 moles fluorine atoms.

Hope this helps!

7 0
3 years ago
Only answer if you know it!
lyudmila [28]
The answer would be D.
6 0
4 years ago
Read 2 more answers
What happens when non-metal atoms ionize? A) They lose electrons B) They gain electrons. C) They lose 2 electrons. D) They do no
nignag [31]
When non-metal atoms ionize they gain electrons.<span> Some examples of this are the halogen elements: F, Cl, Br and I, each, can gain one electron from the respective anions, F-, Cl-, Br-, and I-. O and S, may gain two electrons to form the anions O2- and S2-. This is due to the fact that those elements only need one (in the case of the halogens) or two (in the case of O and S) electrons to reach the most stable configuration of the closest noble gas (with the last shell of electrons full), so they are ready to gain those electrons and form the corresponding ions.</span>
5 0
4 years ago
Read 2 more answers
What is mass in grams of
ELEN [110]

The mass in grams 550 mL of salt water with a density of 1.50 g/cm³ is 825grams.

<h3>DENSITY:</h3>
  • The mass of a substance can be calculated by multiplying the density of the substance by its volume. That is;

Mass = density × volume

  • According to this question, the volume of the salt is 550mL while its density is given as 1.50g/mL. The mass is calculated as follows:

Mass = 1.50g/mL × 550mL

Mass = 825grams.

Therefore, the mass in grams 550 mL of salt water with a density of 1.50 g/cm³ is 825grams.

Learn more about density at: brainly.com/question/16894337

5 0
2 years ago
How many ml of a 14. 0 m nh3 stock solution are needed to prepare 200 ml of a 4. 20 m dilute nh3 solution?.
Lilit [14]

Answer:

60 mL

Explanation:

200 mL =  0.2 L

We know that:

Molarity  =  Moles / Liters

So:

4.20 M = moles / 0.2 L

moles = 4.20 x 0.2 = 0.84

Then:

14.0 M = 0.84 moles / Liters

Liters = 0.84 moles / 14.0 M = 0.06 L

Since they want the answer in mL, convert 0.06 to get 60 mL

5 0
2 years ago
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