Considering the definition of percentage by mass and molality, the molality of Na₃PO₄ in the solution is 0.948 .
- <u><em>Percentage by mass</em></u>
The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.
In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:
Molality is the ratio of the number of moles of any dissolved solute to kilograms of solvent.
The Molality of a solution is determined by the expression:
- <u><em>This case</em></u>
Considering 100 grams as a sample of the solution, then the value of the percentage of concentration given indicates that 13.5 g correspond to Na₃PO₄.
Remember that percent concentration by mass is calculated using the mass of solute and the mass of the solution, which includes both the solute and the solvent. Then:
mass solution= mass solute + mass solvent
100 g= 13.5 g + mass solvent
100 g - 13.5 g= mass solvent
<u><em>86.5 g= mass solvent</em></u>
Then, you know:
- number of moles of solvent= being 163.94 the molar mass of Na₃PO₄, this is the amount of mass a substance contains in one mole.
- mass of solvent= 86.5 grams= 0.0865 kg (being 1000 g= 1 kg)
Then, replacing in the definition of molality:
Solving:
molality= 0.948
Finally, the molality of Na₃PO₄ in the solution is 0.948 .
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