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Nostrana [21]
3 years ago
13

The collapse of the magnetic field inside the ignition coil happens as a

Engineering
1 answer:
Tanzania [10]3 years ago
3 0
Primary coil


See an example below

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Determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron–carbon al
Ahat [919]

Answer:

the carburizing time necessary to achieve a carbon concentration is 31.657 hours

Explanation:

Given the data in the question;

To determine the carburizing time necessary to achieve the given carbon concentration, we will be using the following equation:

(Cs - Cx) / (Cs - C0) = ERF( x / 2√Dt)

where Cs is Concentration of carbon at surface = 0.90

Cx is Concentration of carbon at distance x = 0.30 ; x in this case is 4 mm = ( 0.004 m )

C0 is Initial concentration of carbon = 0.10

ERF() = Error function at the given value

D = Diffusion of Carbon into steel

t = Time necessary to achieve given carbon concentration ,

so

(Cs - Cx) / (Cs - C0) = (0.9 - 0.3) / (0.9 - 0.1)

= 0.6 / 0.8

= 0.75

now, ERF(z) = 0.75; using ERF table, we can say;

Z ~ 0.81; which means ( x / 2√Dt) = 0.81

Now, Using the table of diffusion data

D = 5.35 × 10⁻¹¹ m²/sec at (1100°C) or 1373 K

now we calculate the carbonizing time by using the following equation;

z = (x/2√Dt)

t is carbonizing time

so we we substitute in our values

0.81 = ( 0.004 / 2 × √5.35 × 10⁻¹¹ × √t)

0.81 = 0.004 / 1.4628 × 10⁻⁵ × √t

0.81 × 1.4628 × 10⁻⁵ × √t = 0.004

1.184868 × 10⁻⁵ × √t = 0.004  

√t = 0.004 / 1.184868 × 10⁻⁵

√t = 337.5903

t = ( 337.5903)²  

t = 113967.21 seconds

we convert to hours

t = 113967.21 / 3600

t = 31.657 hours

Therefore, the carburizing time necessary to achieve a carbon concentration is 31.657 hours

7 0
3 years ago
Which of the following is a way to heat or cool a building without using electricity or another power source?
zzz [600]
I believe the answer is: A. Passive heating and cooling.
8 0
3 years ago
Read 2 more answers
Which statement about direct-mail messages is most accurate? Group of answer choices Direct mail is an effective channel for per
torisob [31]

Answer:

Option A

Direct mail is an effective channel for personalized, tangible, three-dimensional messages that are less invasive than telephone solicitations

Explanation:

In modern days, we've seen email marketing hence option B that "Today's companies no longer send direct-mail messages to market their products or services; they rely exclusively on electronic media instead." These companies rely also on direct mails to their clients. Online marketing often uses direct mail for persuasion of their customers hence the last option is also wrong. Considering that already two statements are identified as inaccurate, the option that "All answer choices are accurate statements about direct-mail messages. " is misleading. Therefore, the only most accurate choice about direct-mail is option A

4 0
4 years ago
Your company is planning to build a pipeline to transport gasoline from the refinery to a field of storage tanks. The parameters
AleksandrR [38]

Answer:

The model system will need water flowing at a velocity of 2.07 meters per second to guarantee kinematic similarity in the form of equal Reynolds numbers.

Explanation:

The Reynolds number (Re_{D}) is a dimensionless criterion use for flow regime of fluids, which is defined as:

Re_{D} = \frac{\rho \cdot v\cdot D}{\mu} (Eq. 1)

Where:

\rho - Density, measured in kilograms per cubic meter.

\mu - Dynamic viscosity, measured in kilograms per meter-second.

v - Average flow velocity, measured in meters per second.

D - Pipe diameter, measured in meters.

We need to find the equivalent velocity of water used in the prototype system. In this case, we assume that Re_{D,gas} = Re_{D,w}. That is:

\frac{\rho_{w}\cdot v_{w}\cdot D_{w}}{\mu_{w}} = \frac{\rho_{gas}\cdot v_{gas}\cdot D_{gas}}{\mu_{gas}} (Eq. 2)

Where subindex w is used for water and gas for gasoline.

If we know that \rho_{gas} = 690\,\frac{kg}{m^{2}}, \mu_{gas} = 0.006\,\frac{kg}{m\cdot s}, v_{gas} = 0.5\,\frac{m}{s}, D_{gas} = 1\,m, \rho_{w} = 1000\,\frac{kg}{m^{3}}, \mu_{w} = 0.0018\,\frac{kg}{m\cdot s} and D_{w} = 0.05\,m, then we get the following formula:

57500 = 27777.778\cdot v_{w}

The fluid velocity for the prototype system is:

v_{w} = 2.07\,\frac{m}{y}

The model system will need water flowing at a velocity of 2.07 meters per second to guarantee kinematic similarity in the form of equal Reynolds numbers.

3 0
3 years ago
There are three different types of slings. What determines which type you use?
IgorLugansk [536]

Answer:

I think answer is The type of load, Environment factors

7 0
3 years ago
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