Answer:
Demire karbon ilavesi ne yapar, ne değiştirir, özellikleri nasıl değiştirir, yansımaları nelerdir? Grafiklerde kullanarak detaylı olarak açıklayın. HMK brainly.com/app/profile/7139574 takip et!!!!
Answer:
Explanation:
% Clears variables and screen
clear; clc
% Asks user for input
n = input('Total number of objects: ');
r = input('Size of subgroup: ');
% Computes and displays permutation according to basic formulas
p = 1;
for i = n - r + 1 : n
p = p*i;
end
str1 = [num2str(p) ' permutations'];
disp(str1)
% Computes and displays combinations according to basic formulas
str2 = [num2str(p/factorial(r)) ' combinations'];
disp(str2)
=================================================================================
Example: check
How many permutations and combinations can be made of the 15 alphabets, taking four at a time?
The answer is:
32760 permutations
1365 combinations
==================================================================================
Answer:
32000 bits/seconds
Explanation:
Given that :
there are 16 signal combinations (states) = 2⁴
bits n = 4
and a baud rate (number of signals/second) = 8000/second
Therefore; the number of bits per seconds can be calculated as follows:
Number of bits per seconds = bits n × number of signal per seconds
Number of bits per seconds = 4 × 8000/second
Number of bits per seconds = 32000 bits/seconds
Answer:
if ur mad you may drive faster if ur sad u may drive slower due to the amount of adrenaline and dopamine levels in your body in that given moment
Explanation:
Answer:
a) 2,945 mC
b) P(t) = -720*e^(-4t) uW
c) -180 uJ
Explanation:
Given:
i (t) = 6*e^(-2*t)
v (t) = 10*di / dt
Find:
( a) Find the charge delivered to the device between t=0 and t=2 s.
( b) Calculate the power absorbed.
( c) Determine the energy absorbed in 3 s.
Solution:
- The amount of charge Q delivered can be determined by:
dQ = i(t) . dt
![Q = \int\limits^2_0 {i(t)} \, dt = \int\limits^2_0 {6*e^(-2t)} \, dt = 6*\int\limits^2_0 {e^(-2t)} \, dt](https://tex.z-dn.net/?f=Q%20%3D%20%5Cint%5Climits%5E2_0%20%7Bi%28t%29%7D%20%5C%2C%20dt%20%3D%20%5Cint%5Climits%5E2_0%20%7B6%2Ae%5E%28-2t%29%7D%20%5C%2C%20dt%20%3D%206%2A%5Cint%5Climits%5E2_0%20%7Be%5E%28-2t%29%7D%20%5C%2C%20dt)
- Integrate and evaluate the on the interval:
![= 6 * (-0.5)*e^-2t = - 3*( 1 / e^4 - 1) = 2.945 C](https://tex.z-dn.net/?f=%3D%206%20%2A%20%28-0.5%29%2Ae%5E-2t%20%3D%20-%203%2A%28%201%20%2F%20e%5E4%20-%201%29%20%3D%202.945%20C)
- The power can be calculated by using v(t) and i(t) as follows:
v(t) = 10* di / dt = 10*d(6*e^(-2*t)) /dt
v(t) = 10*(-12*e^(-2*t)) = -120*e^-2*t mV
P(t) = v(t)*i(t) = (-120*e^-2*t) * 6*e^(-2*t)
P(t) = -720*e^(-4t) uW
- The amount of energy W absorbed can be evaluated using P(t) as follows:
![W = \int\limits^3_0 {P(t)} \, dt = \int\limits^2_0 {-720*e^(-4t)} \, dt = -720*\int\limits^2_0 {e^(-4t)} \, dt](https://tex.z-dn.net/?f=W%20%3D%20%5Cint%5Climits%5E3_0%20%7BP%28t%29%7D%20%5C%2C%20dt%20%3D%20%5Cint%5Climits%5E2_0%20%7B-720%2Ae%5E%28-4t%29%7D%20%5C%2C%20dt%20%3D%20-720%2A%5Cint%5Climits%5E2_0%20%7Be%5E%28-4t%29%7D%20%5C%2C%20dt)
- Integrate and evaluate the on the interval:
![W = -180*e^-4t = - 180*( 1 / e^12 - 1) = -180uJ](https://tex.z-dn.net/?f=W%20%3D%20-180%2Ae%5E-4t%20%3D%20-%20180%2A%28%201%20%2F%20e%5E12%20-%201%29%20%3D%20-180uJ)