<h3>
Answer:</h3>
539.56 Joules
<h3>
Explanation:</h3>
- Efficiency of a machine is the ratio of work output to work input expressed as a percentage.
- Efficiency = (work output/work input) × 100%
- Efficiency of a machine is not 100% because so energy is lost due to friction of the moving parts and also as heat.
In this case;
Efficiency = 94%
Work input = 574 Joules
Therefore, Assuming work output is x
94% = (x/574 J) × 100%
0.94 = (x/574 J)
<h3>x = 539.56 J</h3>
Thus, you get work of 539.56 J from the machine
Answer:
The most common type of descriptive research is the case study, which provides an in-depth analysis of a specific person, group, or phenomenon.
Answer: in this question, the only charge in the cavity is Q. Inside the conducting spherical shell, the electric field is zero.
While outside the shell, the electric field is given by: k(q + Q)/r²
Where;
K= is a constant which is given as, 8.99 x 10^9 N m² / C².
Q= source charge which creates the electric field
q= is the test charge which is used to measure the strength of the electric field at a given location.
r= is the radius
Explanation: Inside the conducting spherical shell, the electric field is zero since the Electric field vanishes everywhere inside the volume of a good conductor.
It would move slower/ faster by changing the mass, which would effect the weight and speed.
Answer:
v₁ = 5 m/s
Explanation:
We can use the law of conservation of momentum here:
where,
m₁ = m₂ = m = mass of each disk
u₁ = initial speed of yellow disk = 0 m/s
u₂ = initial speed of orange disk = 5 m/s
v₁ = final speed of yellow disk = ?
v₂ = final speed of orange disk = 0 m/s
Therefore,
<u>v₁ = 5 m/s</u>
