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3 years ago

The graph below represents the motion of four cars, labeled W, X, Y, and Z.

Physics

1 answer:

ycow [4]3 years ago

6 0

Answer:

Answer is A

Explanation:

As we know , for constant velocity we get a straight line.

The formula for this problem is s = vt which is similar to a straight line formula like y = mx + c.

If we put here c = 0 we get the formula for distance and velocity.

So the answer is A.

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After today i might not be here no more

Norma-Jean [14]

Answer:

aw why? are you deleting the app for school?

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2 years ago

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Two identical charges are separated by a distance d. If the distance between them is increased to 3d, what will happen to the fo

belka [17]

A-It will be one-ninth the original force

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3 years ago

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1.3 kg of water, at an initial temperature of 25oC, is heated at a rate of 100 W in a well-insulated container. How much time (i

Leviafan [203]

Answer:

68.25 minutes.

Explanation:

Power = Energy/time or

Power = Heat/time

P = Q/t....................... Equation 1

Q = Pt ........................ Equation 2

Where Q = quantity of heat, P = power, t = time.

Also,

Q = cm(t₂-t₁) ................. Equation 3

Where c = specific heat capacity of water, m = mass of water, t₁ = initial temperature of water, t₂ = final temperature of water.

substitute equation 2 into equation 3

Pt = cm(t₂-t₁) ............... Equation 4

make t the subject of the equation

t = cm(t₂-t₁)/P................ Equation 5

Given: P = 100 W, m = 1.3 kg, t₁ = 25 °C, t₂ = 100 °C.

Constant: 4200 J/kg.K

Substitute into equation 5

t = 1.3(4200)(100-25)/100

t = 409500/100

t = 4095 seconds

t = (4095/60) minutes = 68.25 minutes.

Hence the time it will take the water to reach boiling point = 68.25 minutes

6 0

3 years ago

A young man walks daily through a gridded city section to visit his girlfriend, who lives m blocks East and nblocks North of whe

Arada [10]

Answer:

The man ate eggs.

Explanation:

He should brush his teeth before seeing his girlfriend.

4 0

2 years ago

Railroad car A, with mass 6275 kg, is traveling east at 6.5 m/s along a straight track. It strikes railroad car B, with mass 515

LekaFEV [45]

The speed of A and B immediately after collision is 5.28m/s

<u>Explanation:</u>

Mass of A is 6275kg

Speed of A is 6.5m/s

Mass of B is 5155kg

Speed of B is 3.8m/s

Track is frictionless.

A and B stick together.

speed of attached A and B = ?

mₐsₐ + mᵇsᵇ = (mₐ + mb) s

$6275 X 6.5 + 5155 X 3.8 = ( 6275 + 5155) X s\\\\s = \frac{40787.5 + 19589}{11430}\\ \\s = \frac{60376.5}{11430}\\ \\s = 5.28m/s$

Therefore, The speed of A and B immediately after collision is 5.28m/s

4 0

3 years ago