Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P P and volume V V satisfy th
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1) Magnitude of the net force: 20.8 N
2) Angle: clockwise from positive x-direction
Explanation:
1)
First of all, we need to find the components of the resultant force along the horizontal and vertical direction.
We observe that there are two forces acting along the horizontal direction:
We notice that they act in opposite directions, so the net force in the horizontal direction is the difference between these two forces:
(to the right)
Instead, there is only one force acting in the vertical direction, so the net force in the vertical direction is:
(downward)
Therefore, the magnitude of the net force can be found by using Pythagorean's theorem:
2)
Now we have to find the angle of the resultant net force. We can do it by using the following equation:
where
is the angle, measured as clockwise from the positive x-direction (because the vertical net force is downward)
is the vertical net force
is the horizontal net force
Solving, we find:
And so the angle is
In a direction down with respect to the right.
Learn more about forces:
About addition of vectors:
#LearnwithBrainly
Given :
Mass of water, m = 2 grams.
The temperature of water drops from 31 °C to 29 °C .
The specific heat of water is 4.184 J/(g • °C).
To Find :
Amount of heat lost in this process.
Solution :
We know, heat lost is given by :
Therefore, amount of heat lost in this process is 16.736 J.
Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:
The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.
We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N