It can solidify, it depends on the tempeture.
Answer:
Average acceleration is 
Explanation:
It is given that,
Initial velocity, u = 0
Final velocity, v = 6.5 km/s = 6500 m/s
Time taken, t = 60 s
Acceleration, 

Since, 
So, 
So, the angular acceleration of the missile is
. Hence, this is the required solution.
Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:

The mass of the water accumulated in the bucket after 3.20s is:


To determine the weight of the water accumulated in the bucket, we have:



For the speed of the water before hitting the bucket; we have:


v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:


F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Silver sable is in spiderman lol