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FromTheMoon [43]
1 year ago
8

A light-year is a unit of a. time. c. mass. b. distance. d. density. please select the best answer from the choices provided a b

c d
Physics
2 answers:
11111nata11111 [884]1 year ago
3 0

Answer:

distance

Explanation:

it is the distance traveled by light in one year

Ray Of Light [21]1 year ago
3 0
B. Distance

A light-year has a bit of a deceiving name. Despite the fact that it seems to imply it is a measure of time, this is not of fact correct. A light-year refers to how far light can travel within a year. One light year is approximately 6 trillion miles. Light years are used to measure extremely far distances such as how far the sun is from other stars, or how far away other exoplanets (planets outside our solar system) are.
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Throughout the problem, take the speed of sound in air to be 343 .
anyanavicka [17]

Answer:

A pipe has a length of 1.15 m.

a) Determine the frequency of the first harmonic if the pipe is open at each end. The velocity of sound in air is 343 m/s. Answer in units of Hz

b) What is the frequency of the first harmonic if the pipe is closed at one end?

Answer in units of Hz

Explanation:

8 0
3 years ago
A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hai
Korolek [52]

Answer:

b) 900 W

Explanation:

The breaker trips when the current is equal to 20 A. The power (P) is the ddp (V) multiplied by the current. So, for the electric heater, the current is:

P = V*i

1500 = 120*i

i = 12.5 A

So, to become in 20 A, it's needed 7.5 A, which must come from the hairdryer. Its power must be:

P = 120*7.5

P = 900 W

8 0
3 years ago
What pressing problem did the invention of the cotton gin solve?
AlexFokin [52]
Are you answering a question or asking? You have already seemed to get the answer, A is the correct answer :I
4 0
3 years ago
An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit
lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is 1.127\times 10^7m/s

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

m_1v_1=m_2v_2

where,

m_1\text{ and }v_1 = Initial mass and velocity

m_2\text{ and }v_2 = Final mass and velocity

We are given:

m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s

Putting values in above equation, we get:

238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s

Hence, the velocity of released alpha particle is 1.127\times 10^7m/s

4 0
3 years ago
(a) The electric potential due to a point charge is given by V = kq⁄r where q is the charge, r is the distance from q and k = 8.
LiRa [457]

Answer:

a)  [volts] = [N m / C],

b) The lines or surface that has the same potential are called equipotential

c) the equipotential lines must also be perpendicular to the electric field lines

Explanation:

a) find the units of the volt

the electric potential energy is

             V = k q / r

             V = [N m² / C²] C / m

              V = [N m / C]

The electric potential is defined as

             V = E .s

             V = [N / C] [m]

             V = [N m / C] = [volt]

we see that in the two expressions the same result is obtained therefore the volt is

            [volts] = [N m / C]

b) The lines or surface that has the same potential are called equipotential surfaces, the great utility of these lines or surfaces is that a face can be displaced on it without doing work.

c) The electric potential is defined as the gradient of the electric field

             v =  - \frac{dE}{dx} i^

therefore the equipotential lines must also be perpendicular to the electric field lines

4 0
3 years ago
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