F = normal force by each board on each side
W = weight of the board in between acting in down direction = 95.5 N
f = frictional force in upward direction by each board
= coefficient of friction = 0.663
Using equilibrium of force in Upward direction
f + f = W
f = W/2
f = 95.5/2 = 47.75 N
frictional force is given as
f =
F
47.75 = (0.663) F
F = 72.02 N
Answer:
Part a)
here friction force will accelerate the box in forward direction
Part b)
a = 3.14 m/s/s
Explanation:
Part a)
When truck accelerates forward direction then the box placed on the truck will also move with the truck in same direction
Here if they both moves together with same acceleration then the force on the box is due to friction force between the box and the surface of the truck
So here friction force will accelerate the box in forward direction
Part b)
The maximum value of friction force on the box is known as limiting friction
it is given by the formula

so we have

now the acceleration is given as


Answer:
Explanation:
Intake heat, QH = 100 J
output heat, Qc = 20 J
Work, W = 80 J
TH = 100°C = 373 K
Tc = 10°C = 283 K
TH/ Tc = 373 / 283 = 1.318
QH/Qc = 100 / 20 = 5
for a heat engine, those ratios should be same. so temperature is not correct.
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