Using the appropriate approximations:
dx/L = mλ
d = slit separation
x = fringe spacing
L = distance between slits and screen
m = some integer, used to determine the distance from the central bright fringe to another bright fringe
We don't really need a value for m because we're calculating the distance between any pair of consecutive fringes. Let's just set m = 1
Given values:
d = 1.0mm
L = 2.0m
λ = 480nm
Substitute the terms in the equation with our given values and solve for x:
1.0*10⁻³*x/2 = 480*10⁻9
<h3>x = 0.96mm</h3>
Answer:
<em>Correct choice: b 4H</em>
Explanation:
<u>Conservation of the mechanical energy</u>
The mechanical energy is the sum of the gravitational potential energy GPE (U) and the kinetic energy KE (K):
E = U + K
The GPE is calculated as:
U = mgh
And the kinetic energy is:

Where:
m = mass of the object
g = gravitational acceleration
h = height of the object
v = speed at which the object moves
When the snowball is dropped from a height H, it has zero speed and therefore zero kinetic energy, thus the mechanical energy is:

When the snowball reaches the ground, the height is zero and the GPE is also zero, thus the mechanical energy is:

Since the energy is conserved, U1=U2
![\displaystyle mgH=\frac{1}{2}mv^2 \qquad\qquad [1]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20mgH%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%20%20%20%5Cqquad%5Cqquad%20%5B1%5D)
For the speed to be double, we need to drop the snowball from a height H', and:

Operating:
![\displaystyle mgH'=4\frac{1}{2}m(v)^2 \qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20mgH%27%3D4%5Cfrac%7B1%7D%7B2%7Dm%28v%29%5E2%20%5Cqquad%5Cqquad%20%5B2%5D)
Dividing [2] by [1]

Simplifying:

Thus:
H' = 4H
Correct choice: b 4H
The type of heat that the Sun emits is called UV (Ultra Violet) rays. This is a natural type of heat, but it can also be dangerous if you expose yourself to too much UV heat, causing "sunburns", or even skin cancer.
Answer:
The proton has much greater mass
Explanation:
- Protons and electrons are part of an atom
- Proton exists inside nucleus whereas electron keep moving around the nucleus
- Electrons have negative charge where as protons have positive charge .