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ollegr [7]
3 years ago
5

I need help with the circled one

Physics
1 answer:
Whitepunk [10]3 years ago
7 0
Yes the answer is yes 
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During each cycle of operation a refrigerator absorbs 56 cal from the freezer compartment and expels 81 cal tothe room. If one c
Alexandra [31]

Answer:

138.18 minutes

Explanation:

L_v = Latent heat of water at 0°C = 80 cal/g

m = Mass of water = 570 g

Heat removed for freezing

Q=mL_v\\\Rightarrow Q=570\times 80\\\Rightarrow Q=45600\ cal

Let N be the number of cycles and each cycle removes 56 cal from the freezer.

So,

55\times N=45600\\\Rightarrow N=\frac{45600}{55}

Each cycle takes 10 seconds so the total time would be

\frac{45600}{55}\times \frac{10}{60}=138.18\ minutes

The total time taken to freeze 138.18 minutes

6 0
3 years ago
A 0.76-kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one
sergey [27]

Answer:

1.54 kg

Explanation:

mass of first block (m) = 0.76 kg

acceleration due to gravity (g) = 9.8 m/s

what is the mass (m) of the second block

  • force = kx ⇒ mg = kx

        mg = kx

        where m is the mass, g is the acceleration due to gravity, k is the  

        spring constant and x is the extension

        0.76 x 9.8 = kx

       7.5 = kx

        k = 7.5/x ... equation 1

  • when a second block is attached to the first one the amount of stretch triples (this means that extension (x) = 3x)

        therefore the new mass becomes m + 0.76 and the extension  

        becomes 3x

        with the new mass and extension, mg = kx now becomes

        (m+0.76)g = k(3x) ... equation 2

        Recall that k = 7.5/x from equation 1, substituting this value of k into      

        equation 2 we have

         (m+0.76)g =  \frac{7.5}{x} × (3x)

         (m+0.76)g =  7.5 × 3

          substituting the value of g = 9.8 m/s^{2}

         (m + 0.76) x 9.8 = 7.5 x 3

          m + 0.76 = 22.5 ÷ 9.8

          m + 0.76 = 2.3

          m = 2.3 - 0.76 = 1.54 kg

       

         

       

4 0
4 years ago
Determine the acceleration that results when a 12 N net force is applied to a 3 kg object.
Drupady [299]
A I hope it helpsss youuu ;:))))
8 0
3 years ago
I have got a project about hacks so i need help
zhannawk [14.2K]

Hacks in real life are tricks to help solve a problem with a simple solution.

Say for example, add a pinch of salt to whip egg white faster.

5 0
3 years ago
Read 2 more answers
A hungry 169169 kg lion running northward at 77.377.3 km/hr attacks and holds onto a 31.731.7 kg Thomson's gazelle running eastw
navik [9.2K]

Answer:  75,242.9 m/s

Explanation:

from the question we are given the following parameters

mass of Lion (ML) = 169,169 kg

velocity of lion (VL) = 777,377.7 m/s

mass of Gazelle (Mg) = 31,731.7 kg

velocity of Gazelle (Vg) = 63,863.8 kg

mass of Lion and Gazelle (M) = 200,900.7 kg

velocity of Lion and Gazelle (V) = ?

The first figure below shows the motion of the Lion and Gazelle with their direction.

The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.

from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem

momentum = mass x velocity

momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s

momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s

momentum of the Lion and Gazelle = 200,900.7  x V

now applying Phytaghoras theorem we have

13,089,840,463.7 + 2,026,506,942.46 =  200,900.7 x V

15,116,347,406.16 = 200,900.7 x V

V = 75,242.9 m/s

7 0
3 years ago
Read 2 more answers
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