Acceleration = (change in speed) / (time for the change)
Change in speed = (speed after the change) - (speed before the change)
Change in speed = (65 m/s) - (35 m/s) = 30 m/s
Acceleration = (30 m/s) / (5 s)
<em>Acceleration = 6 m/s²</em>
Answer:
84.6 J
Explanation:
The work done by the force is given by

where
W is the work done
F = 15 N is the force applied
d = 6.0 m is the displacement
is the angle between the force's direction and the displacement
Substituting the numbers into the equation, we find

Answer:

Explanation:
The definition of angular velocity is as follows:

where
is the angular velocity, and
is the frequency.
Frequency can also be represented as:

where
is the period, (the time it takes to conclude a cycle)
with this, the angular velocity is:

The period T of rotation around the sun 365 days, thus, the angular velocity:

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:
Firt conveting to hous

then to minutes

and finally to seconds

thus, angular velocity in rad/second is:

Answer:
a) correct answer is C
, b) 14º from the west to the north, c) v_{1g} = 300.79 km / h
Explanation:
This is a relative speed exercise using the addition of speeds.
1) when it is not specified regarding what is being measured, the medicine is carried out with respect to the Z Earth, therefore the correct answer is C
2 and 3) In this case we must compose the speed using the Pythagorean Theorem.
² =
² +
²
where v_{1a} is the speed of the airplane with respect to the air, v_{1g} airplane speed with respect to the Earth, v_{ag} air speed with respect to the Earth
in this case let's clear the speed of the airplane with respect to the Earth
v_{1g} = √(v_{1a}² - v_{ag}²)
v_{1g} = √ (310² - 75²)
v_{1g} = 300.79 km / h
we find the direction of the airplane using trigonometry
sin θ = v_{ag} / v_{1a}
θ = sin⁻¹ (v_{ag} /v_{1a})
θ = sin⁻¹ (75/310)
θ= 14º
the pilot must direct the aircraft at an angle of 14º from the west to the north