The question is: A tuning fork vibrates at 140 [Hz] and the wave emitted by it propagates with a speed of 340 m / s. Considering the above, it can be correctly stated that the wavelength of the wave emitted by the tuning fork is
Answer: Wavelength of the wave emitted by the tuning fork is 2.43 m.
Explanation:
Given: Frequency = 140 Hz
Speed = 340 m/s
wavelength = ?
Formula used to calculate the wavelength is as follows.

where,
= wavelength
v = speed
f = frequency
Substitute the values into above formula.

Thus, we can conclude that wavelength of the wave emitted by the tuning fork is 2.43 m.
Answer:
The time interval is 
Explanation:
From the question we are told that
The angular acceleration is 
The time taken is 
The angular displacement is 
The angular displacement can be represented by the second equation of motion as shown below

where
is the initial velocity at the start of the 4 second interval
So substituting values

=> 
Now considering this motion starting from the start point (that is rest ) we have

Where
is the angular velocity at rest which is zero and
is the angular velocity after 4.0 second which is calculated as 12 rad/s s

=> 
Answer:
.
Explanation:
Intensity
of the electromagnetic radiation is given by

where
is the distance from the EM source (the center of the sun, in our case), and
is the power output of the sun and it has the value

Since the radius of the sun in meters is
, the intensity
of the electromagnetic radiation at the surface of the sun is

The intensity of the electromagnetic radiation at the surface of the sun is
.
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</span>
To solve the problem it is necessary to apply the Malus Law. Malus's law indicates that the intensity of a linearly polarized beam of light, which passes through a perfect analyzer with a vertical optical axis is equivalent to:

Where,
indicates the intensity of the light before passing through the polarizer,
I is the resulting intensity, and
indicates the angle between the axis of the analyzer and the polarization axis of the incident light.
Since we have two objects the law would be,

Replacing the values,



Therefore the intesity of the light after it has passes through both polarizers is 