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boyakko [2]
3 years ago
8

Racionaliza √7 + 2√5 ÷√7 −√5

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

\frac{\sqrt{7} +2\sqrt{5}}{\sqrt{7}-\sqrt{5}  }\\\\=\frac{\sqrt{7} +2\sqrt{5}}{\sqrt{7}-\sqrt{5}  }*\frac{\sqrt{7} +\sqrt{5}}{\sqrt{7}+\sqrt{5}  }\\\\  =\frac{(\sqrt{7} +2\sqrt{5})(\sqrt{7} + \sqrt{5} )}{(\sqrt{7}-\sqrt{5})(\sqrt{7}+\sqrt{5})\\    }\\\\=\frac{17 +3\sqrt{35} }{2}

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Answer:

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