Answer:
At physiological pH,the carboxylic acid group of an amino acid will be deprotonated while the amino group will be protonated,yielding the zwitter ion form.
Explanation:
Deprotonated means removal of protons in an acid base reaction and protonated means addition of protons in an acid base reaction.
Both protonated and de protonated reaction takes place in catalytic acid bade reaction by changing either it's mass or it's charge.
During formation of zwitter ion, the carboxylic acid will be deprotonated by donating the H+ ion while the amino acid is protonated by taking the H+ ion.
R-CH-COOH R-CH-COO-
I ⇒ I
NH₂ NH₃ (Zwitter ion)
Answer:
(a) ΔU = 7.2x10²
(b) W = -5.1x10²
(c) q = 5.2x10²
Explanation:
From the definition of power (p), we have:
(1)
<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>
(a) We can calculate the energy (ΔU) using equation (1):
(b) The work is related to pressure and volume by:
<em>where p: pressure and ΔV: change in volume = V final - V initial </em>
(c) By the definition of Energy, we can calculate q:
<em>where Δq: is the heat transfer </em>
I hope it helps you!
B) they have no charges and are inside an atom.*
Answer:
Vf = 1.22 mL
Explanation:
If we assume that the pressure is constant and the number of moles does not change, we can say that the volume of the gas is modified in a directly ratio, to the Absolute Temperature.
Let's convert the values:
91°C + 273 = 364K
0.9°C + 273 = 273.9K
Volume decreases if the temperature is decreases
Volume increases if the T° increases
V₁ / T₁ = V₂ / T₂ → 1.63mL /364K = V₂ / 273.9K
V₂ = (1.63mL /364K) . 273.9K → 1.22 mL
